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VladimirAG
2 months ago
8

Diatomic hydrogen gas and diatomic nitrogen gas react spontaneously to form a gaseous product. Give the balanced chemical equati

on (including phases) that describes this reaction

Chemistry
2 answers:
castortr0y [3K]2 months ago
5 0

The balanced chemical equation (including phases) representing the reaction between diatomic hydrogen gas and diatomic nitrogen gas:

\large{\boxed{\bold{3H_2(g)+N_2(g)\:\rightleftharpoons\:2NH_3(g)\:+heat}}}

Further explanation

Stoichiometry in chemistry focuses on the quantitative aspects of chemical reactions, such as calculating volume, mass, and quantities related to the actions of molecules and elements.

In chemical computations, the reaction can be quantified in terms of mass, volume, moles, or a chemical formula, for instance, the molecular formula or the substance level of hydrates.

The reaction equation outlines the chemical formulas of the reactants and products.

A reaction coefficient is a numerical value in the chemical formula representing substances involved in the reaction equation, helping in balancing the reagents and products.

This equation also signifies the states of the substances involved: gas (g), liquid (l), solid (s), and aqueous (aq).

The reaction between hydrogen and nitrogen proceeds as follows:

H₂ (g) + N (g) ⇔ NH3 (g) + heat

The reaction coefficients are balanced by assigning variables to each compound:

aN₂ + bH₂ -> cNH₃

By setting a = 1, we derive:

N: 2a -> c ---> 2 = c

H: 2b -> 3c ---> 2b = 3.2 ---> 2b = 6 -> b = 3

Thus,

b = 3

c = 2

Transforming the equation yields:

N₂ + 3H₂ -> 2NH₃

The synthesis of ammonia is known as the Haber-Bosch process. Hydrogen is acquired through the conversion of natural gas containing propane or butane hydrocarbons, which is then reacted with nitrogen from the air to produce ammonia.

Learn more

The mass of one mole of raindrops

moles of NaOH

moles of water you can produce

Keywords: ammonia production, hydrogen, nitrogen

Alekssandra [3K]2 months ago
5 0

Answer: NH_{3}

Explanation: When diatomic hydrogen and diatomic nitrogen gases react spontaneously, ammonia gas is produced as the outcome.

<pthe reactions="" are="" as="" follows="" since="" all="" substances="" involved="" in="" the="" gas="" phase="" notation="" is="" applied="" to="" molecules.="">

H_{2}_{(g)} + N_{2}_{(g)} ----> NH_{3}_{(g)}

However, this equation is unbalanced, as the right side has 2 hydrogen and 2 nitrogen atoms, which leads to a product containing one nitrogen and three hydrogen atoms.

Thus, upon balancing the equation, we derive:

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

We doubled the amount of diatomic hydrogen, resulting in the generation of 2 moles of ammonia as a product.

Therefore, the fully balanced equation is:

3H_{2}_{(g)} + N_{2}_{(g)} ----> 2NH_{3}_{(g)}

</pthe>
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eduard [2782]
1) Calcium carbonate comprises 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (which is 40.0%)!

2) The mass fraction mentioned is superfluous information.

3) The resulting solution is:

m(Ca)=1.2 g

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m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
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2 months ago
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Liquid nitrogen has a density of 0.807 g/ml at –195.8 °c. if 1.00 l of n2(l) is allowed to warm to 25°c at a pressure of 1.00 at
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Step 1: Convert density from g/mL to g/L; 0.807 g/mL is equivalent to 807 g/L. Step 2: Calculate Moles of N₂; Density = Mass / Volume, or Mass = Density × Volume. Plugging in values, Mass = 807 g/L × 1 L gives us Mass = 807 g. Similarly, Moles = Mass / M.mass, which leads to Moles = 807 g / 28 g.mol⁻¹, giving us Moles = 28.82 moles. Step 3: Apply the Ideal Gas Law to determine Volume of gas occupied; P V = n R T, thus V = n R T / P. Remember to convert temperature to Kelvin (25 °C + 273 = 298 K). Hence, V = (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm, resulting in V = 704.76 L.
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Which of the following refers to a chemical property?. . a. At room temperature, mercury is a liquid, but gold is a solid.. . b.
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VMariaS [2998]

Result:

94.7 %

Explanation:

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2 S + 3 O₂ → 2 SO₃

The stoichiometric mole ratio is:

S: 2 moles

O₂: 3 moles

Moles are calculated as mass divided by molar mass:

n = w / m

where n = moles, w = mass, m = molar mass.

Given:

For sulfur: w = 6.0 g, molar mass = 32 g/mol, so n = 6 / 32 = 0.1871 mol

For oxygen: w = 5.0 g, molar mass = 32 g/mol, thus n = 5 / 32 = 0.15625 mol

Comparing to stoichiometric ratios, sulfur is in excess, so oxygen is the limiting reagent, controlling product formation.

Using proportions:

3 mol O₂ produce 2 mol SO₃, so 1 mol O₂ yields 2/3 mol SO₃.

Therefore, 0.15625 mol O₂ yields (2/3) × 0.15625 = 0.1042 mol SO₃.

Mass of SO₃ produced = n × molar mass = 0.1042 mol × 80 g/mol = 8.340 g

The percentage yield is actual yield divided by theoretical yield times 100:

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Which of the following happens during an endothermic chemical change? (5 points)
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Answer:

Heat is absorbed.

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