At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?

"solid potassium iodide decomposes into iodine gas and solid potassium. Write a a balanced chemical equation for this reaction"

Alekssandra [3086]

Now, construct a balanced equation:

$2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)$

$I_2$ exists in its gaseous form as a diatomic molecule.

3 0

2 months ago

Kayla owns a food truck that sells tacos and burritos. She sells each taco for $3 and each burrito for $7.25. Yesterday Kayla ma

VMariaS [2998]

They overcomplicated things with lots of words. Your initial equation deals with the revenue. I’ll denote tacos as x and burritos as y.
The first equation would be 3x + 7.25y = 595, given that you already have the prices but need the quantities. The second equation will reflect that double the burritos were sold compared to tacos, expressed as y = x + 2.
Hope this clarifies things. If you need further explanation, I can elaborate more.

6 0

3 months ago

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

castortr0y [3046]

Answer: The cell potential for the given reaction stands at 0.50 V

Explanation:

The provided cell reaction is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-reactions are:

Anode oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Cathode reduction half reaction: $Pb^{2+}+2e^-\rightarrow Pb$

Initially, we need to find the cell potential for this reaction.

Utilizing the Nernst equation:

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday's constant = 96500 C

R = gas constant = 8.314 J/mol·K

T = room temperature = $25^oC=273+25=298K$

n = electrons exchanged in oxidation-reduction = 2

$E^o_{cell}$ = standard electrode potential for the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction =?

$[Zn^{2+}]$ = concentration of Zn²⁺ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now substituting all known values into the equation, we arrive at:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

So, the resulting cell potential for this reaction is 0.50 V

5 0

1 month ago

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is

castortr0y [3046]

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the $10^5$ molecules: $16.5 nm\times 10^5=16.5\times 10^5 nm$

$1 nm=10^{-6} mm$

The overall width of a crystal measured in millimeters= $16.5\times 10^5\times 10^{-6} mm=1.65 mm$

The overall width of a crystal is 1.65 mm.

7 0

3 months ago

Read 2 more answers

Based on the crystal-field strengths cl- < f- < h2o < nh3 < h2nc2h4nh2, which octahedral ti (iii) complex below has

eduard [2782]

<span>According to crystal field strength, the Cl ligand results in the longest d-d transition when coordinated with Ti(III) due to its classification as a weak field ligand that causes minimal d orbital splitting.</span>

8 0

1 month ago