If 4.35 g of phosphoric acid are added to 5.25g of KOH, what is the percent yield of the reaction if only 3.15g of potassium pho

Answer: 9.8g

Explanation:

This calculation assumes complete removal of water from the compound.

From there, I will determine the mass of the evaporated water and subtract that from the initial 20.0 g sample.

To do this, follow these steps:

1) Calculate the number of moles of hydrated magnesium sulfate, represented as MgSO₄⋅7H₂O

Number of moles = mass in grams / molar mass

The molar mass of MgSO₄⋅7H₂O can be calculated using the atomic masses of its constituent atoms multiplied by the number of each atom present:

Molar mass = 24.305 g/mol + 32.065 g/mol + 4×15.999g/mol + 7×2×1.008g/mol + 7×15.999 g/mol = 246.471 g/mol

Therefore, moles of MgSO₄⋅7H₂O = 20.0g / 246.471 g/mol = 0.0811 moles

2) Now calculate the number of moles of water, using the ratios derived from the chemical formula:

7 moles of H₂O / 1 mole of MgSO₄⋅7H₂O = x / 0.0811 moles of MgSO₄⋅7H₂O

⇒ x = 0.0811 × 7 moles H₂O = 0.568 moles H₂O

3) Convert moles of H₂O to grams:

Number of moles = mass in grams × molar mass = 0.568 moles × 18.015 g/mol = 10.2 g

4) Thus, the remaining mass is 20.0g - 10.2g = 9.8g

Ethanol, with the formula C2H5OH, is also referred to as Ethyl alcohol.

Explanation:

• The interaction between oil and sodium hydroxide (NaOH) is recognized as the Saponification process.

• A combination of ethanol and water yields a fully homogeneous solution, miscible in all proportions.

• We use a mixture of ethanol and water for the Saponification because it prevents the fat from reacting with atmospheric oxygen.

• This mixture is advantageous as it exhibits lower polarity than water, aiding in the dissolution of non-polar fats, thereby facilitating reaction with sodium hydroxide.

Explanation:

5.5 billion grains of sand (5.5×10^9 grains)

Assuming the amount of brown sand is 6.0%, how many brown grains are found in the bucket?

Grains of brown sand = Percentage of brown sand * Total sand in the bucket

Calculated brown grains = 0.06 * 5.5×10^9 = 0.33 x 10^9 = 3.3 x 10^8 grains

If the concentration of brown sand is 6.0 ppm, what is the number of brown grains in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppm = 6 / 1,000,000 = 0.000006

Calculated brown grains = 0.000006 * 5.5×10^9 = 3.3 x 10^4 grains

If the concentration of brown sand is 6.0 ppb, how many brown grains exist in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppb = 6 / 1,000,000,000 = 0.000000006

Calculated brown grains = 0.000000006 * 5.5×10^9 = 3.3 x 10^1 = 33 grains