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myrzilka
1 month ago
10

If 4.35 g of phosphoric acid are added to 5.25g of KOH, what is the percent yield of the reaction if only 3.15g of potassium pho

sphate is isolated?
Chemistry
1 answer:
lorasvet [2.7K]1 month ago
5 0
We are provided with
4.35 g of phosphoric acid
5.25 g of KOH
3.15 g of K3PO4 produced

The reaction formula is
H3PO4 + 3KOH => K3PO4 + 3H2O

Initially, convert the given masses into moles.
Then, identify the limiting reactant. Afterward, calculate the maximum K3PO4 that can be generated from the limiting reactant.
Finally, compute the percent yield by dividing the actual yield by the theoretical yield.
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To save time you can approximate the initial volume of water to ±1 mL and the initial mass of the solid to ±1 g. For example, if
castortr0y [3046]

Answer:

The correct options include choice 2, 3, and 6.

Explanation:

Density is identified as the mass of a substance per unit volume occupied by that substance.

Density=\frac{Mass}{Volume}

The density remains constant for a given substance, regardless of variations in mass and volume hence it is considered an intensive property.

2. 20.2 g of silver in 21.6 mL of water and 12.0 g of silver also in 21.6 mL of water.

3. 15.2 g of copper in 21.6 mL of water and 50.0 g of copper in 23.4 mL of water.

6. 11.2 g of gold in 21.6 mL of water and 14.9 g of gold in 23.4 mL of water.

The same metals in both instances will yield consistent densities due to the fixed density of the metal.

7 0
1 month ago
A water tank can hold 1 m3 of water. When it’s empty, how much liters is needed to refill it?
Alekssandra [3086]

Response: 1000

Rationale: because 5 cubic meters equals 5000 liters

3 0
1 month ago
Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi
VMariaS [2998]

Answer:

The revised net worth rounded to three significant figures is $80.2 billion.

The donation to charity amounts to $100,250,000.

Explanation:

Initial net worth is $77.0 billion.

Stock gains are $3.20 billion.

Calculating new net worth: $77.0 billion + $3.20 billion = $80.20 billion.

Hence, new net worth to three significant figures is $80.2 billion.

One-eighth of a percent is calculated as (1/8 x 1) / 100 = 0.00125.

The charitable contribution amounts to 0.00125 X $80.2 billion = $100,250,000.

Alternatively, $80,200,000,000 divided by 100 results in $802,000,000.

3 0
1 month ago
A 20.0–milliliter sample of 0.200–molar K2CO3 so­lution is added to 30.0 milliliters of 0.400–mo­lar Ba(NO3)2 solution. Barium c
KiRa [2933]

Respuesta:

0.16 M

Explicación:

Teniendo en cuenta:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

O sea,

Moles =Molarity \times {Volume\ of\ the\ solution}

Dado que:

Para K_2CO_3 :

Molaridad = 0.200 M

Volumen = 20.0 mL

Convierte mL a L:

1 mL = 10⁻³ L

Entonces, volumen = 20.0×10⁻³ L

Los moles de K_2CO_3 son:

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles de K_2CO_3 = 0.004 moles

Para Ba(NO_3)_2 :

Molaridad = 0.400 M

Volumen = 30.0 mL

Convertimos mL a L:

1 mL = 10⁻³ L

Volumen = 30.0×10⁻³ L

Entonces, los moles de Ba(NO_3)_2 son:

Moles=0.400 \times {30.0\times 10^{-3}}\ moles

Moles de Ba(NO_3)_2 = 0.012 moles

Según la reacción:

Ba(NO_3)_2 + K_2CO_3\rightarrow BaCO_3 + 2KNO_3

1 mol de Ba(NO_3)_2 reacciona con 1 mol de K_2CO_3

Por lo tanto,

0.012 mol de Ba(NO_3)_2 reacciona con 0.012 mol de K_2CO_3

Moles disponibles de K_2CO_3 = 0.004 mol

El reactivo limitante es el que está en menor cantidad, entonces K_2CO_3 es el limitante (0.004 < 0.012).

La formación del producto depende del reactivo limitante, así que,

1 mol de K_2CO_3 reacciona con 1 mol de Ba(NO_3)_2 y produce 1 mol de BaCO_3

0.004 mol de K_2CO_3 reacciona con 0.004 mol de Ba(NO_3)_2 y genera 0.004 mol de BaCO_3

Los moles restantes de Ba(NO_3)_2 son: 0.012 - 0.004 = 0.008 mol

El volumen total es 20 + 30 mL = 50 mL = 0.050 L

Por lo que la concentración del ion bario, Ba^{2+}, después de la reacción es:

Molarity=\frac{0.008}{0.050}\ M = 0.16\ M

3 0
2 months ago
How is the periodic law demonstrated in halogens
Anarel [2989]
Halogens are characterized as a group of 7 on the periodic table. Each of these elements has 7 valence electrons, needing just one additional electron to fill their outer shell, resulting in their high reactivity. Moreover, the periodic law indicates that when the elements are arranged by increasing atomic number, similar patterns in their properties emerge. Thus, halogens exhibit comparable behaviors during chemical reactions with one another, which is indeed accurate.
3 0
1 month ago
Read 2 more answers
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