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1 month ago

For c2h3o2−, write an equation that shows how the anion acts as a base.

2 answers:

4 0

The compound Zn(C2H3O2)2 is a derivative of zinc acetic acid. Its molecular makeup indicates it consists of zinc (Zn), carbon (C), hydrogen (H), and oxygen (O). Below is an equation demonstrating the basic behavior of the anion:

C2H3O2−(aq)+H2O(l)⇌HC2H3O2(aq)+OH−(aq)

lorasvet [2.7K]1 month ago

3 0

Explanations:- The acetate ion serves as the conjugate base of a weak acid, acetic acid. According to the Bronsted-Lowry acid-base theory, "Acids donate protons, while bases accept protons."

For acetate to function as a base, it needs to accept a proton. Water acts as an amphoteric substance, meaning it can behave both as an acid and a base. Let us now write the reaction between acetate ion and water to illustrate how it operates as a base.

$C_2H_3O_2^-(aq)+H_2O(l)\rightleftharpoons HC_2H_3O_2(aq)+OH^-(aq)$

In this reaction, the acetate ion has taken a proton from water, identifying it as a base, while water donates a proton, qualifying it as an acid.

Furthermore, acetic acid is the conjugate acid of the acetate ion, while hydroxide ion is the conjugate base of water.

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A 2 L bottle containing only air is sealed at a temperature of 22°C and a pressure of 0.982 atm. The bottle is placed in a freez

Anarel [2989]

The answer is.997 atm. 1. Identify the combined gas law equation... (P1V1/T1 = P2V2/T2) 2. Gather our values... P1=.982 atm P2=? (this is what we want to find) V1= 2 L V2= 1.8 L T1= 22 C = 295 K T2= -3 C = 270 K - Note: Always convert to Kelvin. To do this, add 273 to the Celsius value. 3. Rearranging the formula to suit this problem... (P2=P1V1T2/V2T1) 4. Insert our values... P2=.982 atm x 2 L x 270 K / 1.8 L x 295 K 5. Calculate and the result should yield....997 atm - If you require further clarification or assistance, feel free to reach out and I'll be happy to help!

5 0

1 month ago

When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq), 3.14 kJ of heat are produced. Determine the enthalpy change per mole o

Alekssandra [3086]

Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.

Explanation:

First, we need to determine the moles of Zn and HCl.

$\text{Moles of }Zn=\frac{\text{Mass of }Zn}{\text{Molar mass of }Zn}$

The molar mass of Zn is 65 g/mole

$\text{Moles of }Zn=\frac{1.34g}{65g/mole}=0.0206mole$

and,

$\text{Moles of }HCl=\text{Concentration of }HCl\times \text{Volume of solution}=0.750M\times 0.0600=0.0450mole$

Next, we must identify the limiting reagent and the excess reagent.

The chemical reaction given is:

$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$

According to the balanced reaction we find that

1 mole of $Zn$ reacts with 2 moles of $HCl$

Thus, 0.0206 moles of $Zn$ react with $0.0206\times 2=0.0412$ moles of $HCl$

This leads us to determine that $HCl$ is the excess reagent because the moles provided exceed the required moles, while $Zn$ is limiting and restricts product formation.

Now to find the enthalpy change for each mole of zinc reacting in this reaction.

From the reaction we gather that,[ [TAG_59]]

0.0206 moles of Zn yield heat = 3.14 kJ

This implies that 1 mole of Zn generates heat = $\frac{3.14kJ}{0.0206mol}=152.4kJ/mol$

Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.

5 0

1 month ago

It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it

Anarel [2989]

3,048 minutes. Explanation: 762 divided by 5, then multiply that number by 20.

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16 days ago

Calculate the change in internal energy of the following system: a 100.0-g bar of gold is heated from 25 ∘C to 50 ∘C during whic

castortr0y [3046]

According to the Law, the variation in internal energy (U) of the system is equal to the total of the heat added to the system (q) plus the work performed ON the system (W)
ΔU = q + W 

In response to the first question, 0.653 kJ of heat energy is extracted from the system (balloon) while 386 J of work is applied to the balloon, leading to 
ΔU = -653J + 386J 
=-267J 
Thus, the internal energy reduces by 267 J 

For the second question, 322 J of heat is supplied to the system (gold bar) while no work is undertaken on the gold bar, marking this as an isochoric/isovolumetric process, thus 
ΔU = 322J + 0 
=322J 
Hence, internal energy rises by 322 J

8 0

15 days ago

Read 2 more answers

Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G

Anarel [2989]

1) The chemical equation is

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) Molar ratios are as follows:

1 mol Cu: 2 moles AgNO3: 1 mol Cu (NO3)2: 2 mol Ag

3) Converting 12.83 * 10^23 atoms of Cu to moles gives:

12.83 * 10^23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Using the ratios:

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) To convert 4.262 mol of silver to grams, use the atomic weight of silver:

mass = moles × atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

Answer: 459.9 g

5 0

1 month ago