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5 days ago

For c2h3o2−, write an equation that shows how the anion acts as a base.

2 answers:

4 0

The compound Zn(C2H3O2)2 is a derivative of zinc acetic acid. Its molecular makeup indicates it consists of zinc (Zn), carbon (C), hydrogen (H), and oxygen (O). Below is <span> an equation demonstrating the basic behavior of the anion:

</span>

C2H3O2−(aq)+H2O(l)⇌<span>HC2H3O2(aq)+OH−(aq)</span>

lorasvet [956]5 days ago

3 0

Explanations:- The acetate ion serves as the conjugate base of a weak acid, acetic acid. According to the Bronsted-Lowry acid-base theory, "Acids donate protons, while bases accept protons."

For acetate to function as a base, it needs to accept a proton. Water acts as an amphoteric substance, meaning it can behave both as an acid and a base. Let us now write the reaction between acetate ion and water to illustrate how it operates as a base.

$C_2H_3O_2^-(aq)+H_2O(l)\rightleftharpoons HC_2H_3O_2(aq)+OH^-(aq)$

In this reaction, the acetate ion has taken a proton from water, identifying it as a base, while water donates a proton, qualifying it as an acid.

Furthermore, acetic acid is the conjugate acid of the acetate ion, while hydroxide ion is the conjugate base of water.

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How much volume (in cm3) is gained by a person who gains 11.1 lbs of pure fat?

Anarel [852]

The density of human fat is $0.918 g/cm^{3}$ . The mass of the pure fat is 11.1 lbs.

First, convert the mass from pounds to grams as follows:

1 lb=453.592 g

Thus,

$11.1 lb\rightarrow 11.1\times 453.592 g=5034.875 g$

Density is defined as mass per unit volume, meaning volume can be calculated as:

$V=\frac{m}{d}$

By substituting the values,

$V=\frac{5034.875 g}{0.918 g/cm^{3}}=5484.61 cm^{3}$

Consequently, the volume gained by the individual will be $5484.61 cm^{3}$ .

6 0

8 days ago

The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr

lions [985]

Response:

The pKa value is 13.0.

Clarification:

pKa + pKb = 14

For trimethylamine, Kb = 6.3 × $10^{-5}$

Calculating pKb: pKb = - log (6.3 × $10^{-5}$ )

= 1.0

Thus, pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Verification: The typical range for pKa in weak acids is from 2 to 13.

8 0

5 days ago

Primordial swamps decomposing under ancient seas and tons of rock layers gave rise to an important fuel used today. That fuel is

lorasvet [956]

I think the right choice is C. Coal, as it's utilized in making a multitude of products across the globe. I trust this information is useful to you.:)

8 0

21 hour ago

Read 2 more answers

To save time you can approximate the initial volume of water to ±1 mL and the initial mass of the solid to ±1 g. For example, if

castortr0y [923]

Answer:

The correct options include choice 2, 3, and 6.

Explanation:

Density is identified as the mass of a substance per unit volume occupied by that substance.

$Density=\frac{Mass}{Volume}$

The density remains constant for a given substance, regardless of variations in mass and volume hence it is considered an intensive property.

2. 20.2 g of silver in 21.6 mL of water and 12.0 g of silver also in 21.6 mL of water.

3. 15.2 g of copper in 21.6 mL of water and 50.0 g of copper in 23.4 mL of water.

6. 11.2 g of gold in 21.6 mL of water and 14.9 g of gold in 23.4 mL of water.

The same metals in both instances will yield consistent densities due to the fixed density of the metal.

7 0

3 days ago

The concentration of Si in an Fe-Si alloy is 0.25 wt%. What is the concentration in kilograms of Si per cubic meter of alloy?

KiRa [971]

Answer: The mass of Si in kilograms is, $19.55kg/m^3$

Explanation:

Given that the Si concentration in an Fe-Si alloy is 0.25 weight percent, this translates to:

Mass of Si = 0.25 g = 0.00025 kg

Mass of Fe = 100 - 0.25 = 99.75 g = 0.09975 kg

Density of Si = $2.32g/cm^3=2.32\times 10^6g/m^3$

Density of Fe = $7.87g/cm^3=7.87\times 10^6g/m^3$

Next, we need to find the quantity of Si in kilograms per cubic meter of alloy.

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\text{Volume of 100 g of alloy}}$

Si concentration in kilograms = $\frac{\text{Weight of Si in 100 g of alloy}}{\frac{\text{Wight of Fe}}{\text{Density of Fe}}+\frac{\text{Wight of Si}}{\text{Density of Si}}}$

By substituting all the provided values into this formula, we arrive at:

Si concentration in kilograms = $\frac{0.00025kg}{\frac{99.75g}{7.87\times 10^6g/m^3}+\frac{0.25g}{2.23\times 10^6g/m^3}}$

Si concentration in kilograms = $19.55kg/m^3$

Hence, the mass of Si in kilograms is, $19.55kg/m^3$

5 0

8 days ago