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1 month ago

For c2h3o2−, write an equation that shows how the anion acts as a base.

2 answers:

4 0

The compound Zn(C2H3O2)2 is a derivative of zinc acetic acid. Its molecular makeup indicates it consists of zinc (Zn), carbon (C), hydrogen (H), and oxygen (O). Below is an equation demonstrating the basic behavior of the anion:

C2H3O2−(aq)+H2O(l)⇌HC2H3O2(aq)+OH−(aq)

lorasvet [2.7K]1 month ago

3 0

Explanations:- The acetate ion serves as the conjugate base of a weak acid, acetic acid. According to the Bronsted-Lowry acid-base theory, "Acids donate protons, while bases accept protons."

For acetate to function as a base, it needs to accept a proton. Water acts as an amphoteric substance, meaning it can behave both as an acid and a base. Let us now write the reaction between acetate ion and water to illustrate how it operates as a base.

$C_2H_3O_2^-(aq)+H_2O(l)\rightleftharpoons HC_2H_3O_2(aq)+OH^-(aq)$

In this reaction, the acetate ion has taken a proton from water, identifying it as a base, while water donates a proton, qualifying it as an acid.

Furthermore, acetic acid is the conjugate acid of the acetate ion, while hydroxide ion is the conjugate base of water.

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A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W

eduard [2782]

Answer:

The salt identified is barium chloride.

Explanation:

$BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX$

The moles of barium sulfate produced are $\frac{11.21 g}{233.38 g/mol}=0.0480 mol$

per the reaction, 1 mole of barium sulfate arises from 1 mole of $BaX_2$ .

Therefore, 0.0480 moles result from:

$\frac{1}{1}\times 0.0480 mol=0.0480 mol$ of $BaX_2$ .

The quantity of $BaX_2$ used amounts to 10.00 g

Moles of $BaX_2$ = \frac{10.00 g}{\text{Molar mass}}[/tex]

$0.0480 mol=\frac{10.00}{\text{Molar mass}}$

The molar mass of $BaX_2$ is 208.33 g/mol

The closest answer to our calculation is $BaCl_2=208.2 g/mol$ .

The correct identification is barium chloride, which has a molar mass of 208.2 g/mol.

8 0

26 days ago

If angle ABE = 2n + 7 and angle EBF=4n-13, find angle ABE.

VMariaS [2998]

Answer:

Angle ABE measures 27°.

Explanation:

Refer to the attached diagram related to this question.

The given values are ∠ABE=2n+7 and ∠EBF=4n-13.

Clearly seen in the diagram, ∠ABE and ∠EBF are equal in measure.

$m\angle ABE=m\angle EBF$

$2n+7=4n-13$

Move variable components to one side of the equation.

$7+13=4n-2n$

$20=2n$

Split both sides by 2.

$10=n$

The solution for n arrives at 10.

The next step is to calculate ∠ABE.

$\angle ABE=2(10)+7=20+7=27$

Consequently, the measurement of angle ABE is 27°.

4 0

1 month ago

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when

castortr0y [3046]

Answer: The cell potential for the given reaction stands at 0.50 V

Explanation:

The provided cell reaction is:

$Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)$

The half-reactions are:

Anode oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Cathode reduction half reaction: $Pb^{2+}+2e^-\rightarrow Pb$

Initially, we need to find the cell potential for this reaction.

Utilizing the Nernst equation:

$E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}$

where,

F = Faraday's constant = 96500 C

R = gas constant = 8.314 J/mol·K

T = room temperature = $25^oC=273+25=298K$

n = electrons exchanged in oxidation-reduction = 2

$E^o_{cell}$ = standard electrode potential for the cell = +0.63 V

$E_{cell}$ = cell potential for the reaction =?

$[Zn^{2+}]$ = concentration of Zn²⁺ = 3.5 M

$[Pb^{2+}]$ = $2.0\times 10^{-4}M$

Now substituting all known values into the equation, we arrive at:

$E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}$

$E_{cell}=0.50V$

So, the resulting cell potential for this reaction is 0.50 V

5 0

18 days ago

Using the equation pH = -log [H+], determine the pH of a solution with a hydrogen ion concentration, or [H+], of 1x10-5. HINT: l

castortr0y [3046]

Response:

The result is a pH of 7. I’m uncertain about the mechanics of Hydrochloric acid reactions

8 0

24 days ago

On the axes provided, label pressure on the horizontal axis from O mb to 760 mb and volume on the vertical axis from O to 1 mL.

KiRa [2933]

Answer:

Please refer to the attached image for the graph with labeled axes and points.

Explanation:

This is a guide to fulfilling the instructions along with essential notes for understanding how to create such graphs:

1) The horizontal axis should indicate pressure ranging from 0 mb to 760 mb, while the vertical axis corresponds to volume ranging from 0 to 1 mL.

The x-axis captures the independent variable, and the y-axis records the dependent variable. Both axes must be accurately labeled, showing the variable names and their respective units.

In this context, the origin, (0,0), signifies the intersection of the axes at a pressure of 0 mb and a volume of 0.0 milliliters.

2) Allocate values for the divisions on the axes to maximize the usage of space on both.

An effective graph aims to utilize the entire space on both axes; for this, identify the maximum values for pressure and volume, and determine the corresponding marks.

The pressure range along the x-axis is [90, 760 mb], suggesting large divisions of 100 mb, with the farthest right mark at 800 mb. You can then subdivide each 100 mb interval into 10 smaller sections, using small divisions of 10 mb (my example employs 4 sections of 25 mb, but 10 mb is preferable).

The volume's range for the vertical axis is [0.1, 0.8], so it’s best to use divisions set at 0.1 ml.

3) Next, identify and label the points as follows:

(90, 0.9) ⇒ 90 mb, 0.9 ml

(100, 0.8) ⇒ 100 mb, 0.8 ml

(400, 0.2) ⇒ 400 mb, 0.2 ml

(600, 0.15) ⇒ 600 mb, 0.15 ml

(760, 0.1) ⇒ 760 mb, 0.1 ml

The points represented as (x, y) are referred to as ordered pairs, indicating that the sequence is significant: the first number denotes the independent variable whereas the second denotes the dependent variable.

Thus, for the point (90, 0.9), 90 indicates a pressure of 90 mb and 0.9 indicates a volume of 0.9 ml.

To find (600, 0.15), since the horizontal increments are valued at 0.1, you should place the second coordinate of the point between the marks corresponding to 0.1 and 0.2 ml.

This allows you to accurately plot each point on the graph.

5 0

18 days ago

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