In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

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In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

deck. a winning "blackjack" hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack hands?

Mathematics

1 answer:

tester [12K] · Answer 1 · 2026-02-16T23:16:15+03:00

The blackjack hand consists of:

One of the four aces: probability = 4 / 52

One of the sixteen cards valued at 10 points (10, jack, queen, king): probability = 16 / 52

Assuming cards are dealt sequentially without replacement,

The total probability of a blackjack hand is:

<span>P = (first card ace * second card 10-point) + (first card 10-point * second card ace)</span>

P = (4 / 52) * (16 / 51) + (16 / 52) * (4 / 51)

P = 0.04827, or approximately 4.83%

Therefore, the chance of receiving a blackjack hand is around 4.83%.

In the game of blackjack played with one​ deck, a player is initially dealt 2 different cards from the 52 different cards in the

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the