Answer:
The distance covered by the minutes hand is 39.60 cm.
Explanation:
Note: A clock has a circular shape, where the minutes hand acts as the radius, and its motion creates an arc.
Length of an arc is calculated as ∅/360(2πr)
L = ∅/360(2πr).................... Equation 1π
Here, L represents the arc’s length, ∅ is the angle made by the arc, and r is the arc’s radius.
Given: ∅ = 252°, r = 9 cm, π = 3.143.
Upon substituting these values into equation 1,
L = 252/360(2×3.143×9)
L = 0.7×2×3.143×9
L = 39.60 cm.
Thus, the distance traversed by the minutes hand is 39.60 cm.
a) Average power: 1425 W
b) Instantaneous power at 3.0 seconds: 2850 W
Given that the object moves along the ramp with uniform acceleration due to a constant force, we can apply the suvat equation:
s = 18 m (the distance covered along the ramp)
u = 0 (initial speed)
t = 3.0 s (time taken)
a is the acceleration of the object along the ramp
Calculating the acceleration 'a' using this data,
Next, we use Newton's second law to determine the net force acting on the object:
This net force consists of the applied force acting forward and the backward component of weight, allowing us to calculate the applied force.
m = 24 kg (mass of the object)
Now, we can compute the work done by the applied force, which runs parallel to the ramp:
s = 18 m (displacement)
The average power required is thus determined.
b) The instantaneous power at any point during the motion can be calculated using:
where F is the force applied and v is the object's velocity.
With the previously calculated applied force, as this is uniformly accelerated motion, we can also find the velocity at the end of the 3.0 seconds using the suvat equation:
E) This planet has a greater diameter than any of the four terrestrial planets that orbit close to the Sun.
B) A substantial amount of rocky material accumulated to create a planet larger than Earth.
(Which two statements are the most accurate)
- A, C, and D simply do not make sense.
