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MaRussiya
1 month ago
11

An object of mass 24kg is accelerated up a frictionless place incline at an angle of 37° with horizontal by a constant force, st

arting at the bottom from, covers a distance of 18m in 3.0sec.
a)What is the average power required to accomplish the process?
b) what is the instantaneous power required at the ends of 3.0secods interval?
Physics
1 answer:
inna [3.1K]1 month ago
8 0
a) Average power: 1425 W b) Instantaneous power at 3.0 seconds: 2850 W Given that the object moves along the ramp with uniform acceleration due to a constant force, we can apply the suvat equation: s = 18 m (the distance covered along the ramp) u = 0 (initial speed) t = 3.0 s (time taken) a is the acceleration of the object along the ramp Calculating the acceleration 'a' using this data, Next, we use Newton's second law to determine the net force acting on the object: This net force consists of the applied force acting forward and the backward component of weight, allowing us to calculate the applied force. m = 24 kg (mass of the object) Now, we can compute the work done by the applied force, which runs parallel to the ramp: s = 18 m (displacement) The average power required is thus determined. b) The instantaneous power at any point during the motion can be calculated using: where F is the force applied and v is the object's velocity. With the previously calculated applied force, as this is uniformly accelerated motion, we can also find the velocity at the end of the 3.0 seconds using the suvat equation:
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