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Lilit
3 months ago
10

You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball

descend together a distance of 0.150 m.
How much work do your hands do on the volleyball in the process of stopping it?
What is the magnitude of the force (assumed constant) that your hands exert on the volleyball?
Physics
1 answer:
Softa [3K]3 months ago
3 0

Explanation:

The amount of work performed corresponds to the variation in energy.

W = ΔKE

W = 0 − ½mv²

W = -½ (0.270 kg) (-7.50 m/s)²

W = -7.59 J

Work can be defined as the product of force and distance.

W = Fd

-7.59 J = F (-0.150 m)

F = 50.6 N

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