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astra-53
1 month ago
5

To practice Problem-Solving Strategy 16.1 Sound Intensity. A rescue team is searching for Andrew, a geologist who was stranded w

hile conducting research in the mountains of Colorado. The team uses electronic listening devices in order to detect any shouts for help. The sound waves from his shouts reaching the base camp can be approximated by a sinusoidal wave with a frequency f = "520" Hz and displacement amplitude A = 4.50×10−8 m , where the sound wave properties are valid at the base camp where the measurements are being made. What sound intensity level will the rescue team measure from the frightened researcher? Assume the speed of sound is v=333m/s and the density of air rho = 1.28 kg/m3 .
Physics
1 answer:
Yuliya22 [3.3K]1 month ago
3 0

Answer:

Explanation:

The intensity of a wave is calculated as

2 π² f²A²v p

= 2 π² (520)² (4.5 ×10∧-8)² (333) (1.28)

I= 4.607 × 10∧-6

Intensity level is

β = 10 dB ㏒ (I÷Io)

    =10 dB ㏒ (4.607 × 10∧-6 ÷ 10∧-12)

β = 66.6 dB

The bulk modulus is

B = v² p

 = (333)² (1.28)

 = 1.419 ×10∧5 Pa

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inna [3103]

Answer:

The wire length is 32 inches.

Explanation:

According to the question,

The pipe's length = 60 inches

The pipe's circumference = 4 inches

Now,

The wire wraps around the pipe for 8 complete turns.

Now, with 2πr = 4, we find that

r = 2/π

Thus,

The radius, r = 2/π

The wire's length can be calculated as,

Length = Number of turns x Circumference of the pipe

So, length of wire = 8 x 4 = 32 inches.

Consequently, the wire length is 32 inches.

7 0
2 months ago
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The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha
Maru [3345]

Answer:

A) 5.1*10^10m B) 5.4*10^6m

Explanation:

Utilizing the formula for surface radiation P (energy per second in Watts) = emissivity constant * surface area * Stefan-Boltzmann constant * Temperature in Kelvin^4 *

2.7*10^31 = 1* 5.67*10^-8*A*11000^4

Rearranging to solve for A = 2.7*10^31 / (5.67*10^-8*1.46*10^16) = 0.3261*10^23m^2

Assuming the shape is spherical, the surface area is = 4πR^2 (radius of Rigel)

R = √(0.3261*10^23 / 4*π) = 5.1 * 10^10m

B) repeating the same calculation

2.1 *10^23 = 1*A*5.67*10^-8*10000^4 where A is the surface area of Procyon

Rearranging gives A = 2.1*10^23/(5.67*10^-8*10^16)

A = 0.37*10^15

Assuming the star is spherical;

A = 4πR^2 where R is Procyon's radius

R = √(0.37*10^15/4π) = 5.4*10^6m

4 0
1 month ago
A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno
Ostrovityanka [3204]

Answer

Given data:

height of the dam = 15 m

effective area for water flow = 2.3 x 10⁻³ m²

Applying the principle of energy conservation:

m g h = \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v= \sqrt{2\times 9.8 \times 15}

v= \sqrt{294}

v = 17.15 m/s

water discharge

Q = A V

Q = 2.3 x 10⁻³ x 17.15

Q = 0.039 m³/s

3 0
2 months ago
A fan that is switched on for 1 minute uses 500 W usefully but also wastes 300 W through the emission of sound and heat. What's
Ostrovityanka [3204]

Explanation:

Efficiency can be expressed as the ratio of useful output to the total power consumed. E = \frac{useful}{total}

The fan delivers 500W as useful output while wasting 300W. Thus, the overall power consumed equals 800W (500 + 300).

6 0
1 month ago
In the past, salmon would swim more than 1130 km (700 mi) to spawn at the headwaters of the Salmon River in central Idaho. The t
Keith_Richards [3271]

Answer:

E_t_o_t_a_l=7.603MJ

Explanation:

The overall energy expenditure of the salmon, which corresponds to its swimming upstream effort, W, is linked to its specific mechanical power. Mechanical \ power calculated per unit mass can be derived from the following equation:

\frac{p}{m}=\frac{1}{m}|\frac{dW}{dt}|=2W/kg\\\frac{1}{2}|\frac{W}{22\times 24 \times 60\times 60}|=2\\\\W=7.603MJ

As a result, the total energy utilized during the 22-day journey is 7.603 MJ

6 0
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