1. What volume of toluene do you need to add to 1 mL of ethyl acetate to make an equi-molar mixture? The density of ethyl acetat

On occasion, it has been found that the oxidation of borneol doesn't go to completion (possibly because of poor stirring or insu

VMariaS [2998]

Response:

Examine the explanation

Explanation:

In this scenario, Nitrogen (N) experiences oxidation while Chlorine (Cl) undergoes reduction.

In response to your inquiry:

N is oxidized from an oxidation state of -3 to -1.

Cl is reduced from an oxidation state of +1 to -1.

At this point,

Borneol will likely exhibit a lower Rf due to its boiling point.

3 0

1 month ago

The dipole moment (μ) of hbr (a polar covalent molecule) is 0.797d (debye), and its percent ionic character is 11.8 % . estimate

Alekssandra [3086]

The dipole moment u can be calculated using the formula
U = rq
Where u represents the dipole moment
R indicates the bond length
Q = 1.6x10-19 C
Hence, R = u/q
R = (0.797 d) ( 3.34x10^-30 Cm/ 1 d) /( 1.6x10^-19 C)(0.118)
R = 1.41x10^-10 m
<span>R = 141 pm</span>

6 0

1 month ago

A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista

eduard [2782]

Details:

The equation to calculate work done is defined as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

where, k = proportionality constant = $8.99 \times 10^{9} Jm/C^{2}$

$q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C$

$q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C$

d = separation distance = 0.45 nm = $0.45 \times 10^{-9} m$

Now we will insert the given values into the formula above to compute the work done as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

= $\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}$

= $3.68 \times 10^{-18} J$

Thus, we can conclude that the work needed to increase the distance between the two ions to infinity is $3.68 \times 10^{-18} J$ .

7 0

2 months ago

In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay

lorasvet [2795]

Answer:

1984

Explanation:

Utilizing the equation;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half-life of the radioactive isotope

t= age of the wine

Ao= initial activity of the wine

A= activity at time = t

Substituting values, we have 0.693/12.3 = 2.303/t log (5.5/0.688)

0.693/12.3 = 2.079/t

0.056 = 2.079/t

t= 2.079/0.056

t= 37 years

7 0

2 months ago

A generic element, Z, has two isotopes, 45Z and 47Z, and an average atomic mass of 45.36 amu. The natural abundances of the two

lorasvet [2795]

The isotopic mass of 47Z is calculated to be 46.96 amu. Isotopes of a single element differ in neutron count, and to ascertain the relative atomic mass, we consider each isotope's mass weighted by their natural abundance. This provided a computation to derive the mass of 47Z.

5 0

1 month ago