When balanced, which equation would have the coefficient 3 in front of any of the reactants? Zn + HCl ZnCl2 + H2 H2SO4 + B(OH)3

To address this issue, we can apply the following equation:

w = (mass of solute) / (mass of solution)

w - percentage

It is important to note that the mass of the solution is the sum of the mass of the solute and the mass of the water.

<span>w = mass CaCl2/(mass of water + mass of CaCl2)
</span>
mass of water = x

0.35 = 36 / (x + 36)

0.35 × (x + 36) = 36

0.35x + 12.6 = 36

0.35x = 23.4

x = 66.86 g of water is required

Is this a multiple-choice question? Is there an educational issue that needs to be resolved?

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Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution: 0.0328 M

The amount of HCl in the 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution: 0.0245 M

The amount of NaOH in the 0.100 L solution = 0.00245 moles

3) Determining the concentration of hydrochloric acid in the final solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl from the original 0.0082 moles of HCl.

The total volume of the mixture becomes 0.100 L + 0.250 L = 0.350 L

Remaining moles of unreacted HCl = 0.0082 moles - 0.00245 moles = 0.00575 moles

Concentration of the remaining HCl:

0.0164 molar concentration of hydrochloric acid in the resulting solution.