Answer: The change in enthalpy for each mole of zinc involved in the reaction is 152.4 kJ/mol.
Explanation:
First, we need to determine the moles of Zn and HCl.

The molar mass of Zn is 65 g/mole

and,

Next, we must identify the limiting reagent and the excess reagent.
The chemical reaction given is:

According to the balanced reaction we find that
1 mole of
reacts with 2 moles of 
Thus, 0.0206 moles of
react with
moles of 
This leads us to determine that
is the excess reagent because the moles provided exceed the required moles, while
is limiting and restricts product formation.
Now to find the enthalpy change for each mole of zinc reacting in this reaction.
From the reaction we gather that,[ [TAG_59]]
0.0206 moles of Zn yield heat = 3.14 kJ
This implies that 1 mole of Zn generates heat = 
Hence, the enthalpy change per mole of zinc involved in this reaction amounts to 152.4 kJ/mol.