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Step2247
3 months ago
7

A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at

38.0 cm/s. Find its (a) angular frequency and (b) wave number. (c) Write a mathematical expression describing the displacement y of this wave (in centimeters) as a function of position and time. Assume the maximum displacement occurs when t = 0.
Physics
1 answer:
Ostrovityanka [3.2K]3 months ago
4 0

Answer

Given:

Wavelength = λ = 18.7 cm

                  = 0.187 m

Amplitude, A = 2.34 cm

Velocity, v = 0.38 m/s

A)  Calculate the angular frequency.

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

Angular frequency,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) Calculate the wave number:

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

Since the wave is traveling in the -x direction, the sign is positive between x and t

y (x, t) = A sin(k x - ω t)

y (x, t) = 2.34 sin(33.59 x - 12.75 t)

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No, that statement isn't correct because an atom is made up of two main regions and three subatomic particles: protons, neutrons, and electrons. Each of these particles is smaller than the atom itself, qualifying them as subatomic particles. To be classified as an atom, both protons and electrons are essential — for example, hydrogen has one proton and one electron. Neutrons don't influence the atomic electrical charge; they only add to the atomic mass.
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3 months ago
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When water freezes, it expands about nine percent. What would be the pressure increase inside your automobile engine block if th
Keith_Richards [3271]

Answer:

The increase in pressure within the engine block of the car amounts to 1782.18 ATM.

Explanation:

Provided:

the volume change of water, ΔV = 9%

the bulk modulus for ice, K = 2 x 10⁹ N/m²

It is calculated using the bulk modulus formula;

K = -V\frac{dP}{dV}

so when the water freezes, the pressure increase in the automobile engine block is;

dP = K(\frac{dV}{V} )\\\\dP = K(\frac{0.09V}{V} )\\\\dP = 0.09K\\\\dP = 0.09 (2*10^9)\\\\dP = 1.8 *10^{8} \ N/m^2\\\\dP = 1782.18 \ ATM

Thus, the final pressure increase inside the automobile engine block is 1782.18 ATM.

6 0
3 months ago
Suppose Mitch Marner (mass=80kg) and Zdano Chara (mass=116kg) collide head-on at the blue line when Marner is skating 10m/s and
Maru [3345]

Answer:

1) Marner experiences a greater change in velocity

2) This happens because Chara has a greater mass compared to Marner, leading to a smaller change in velocity for Chara

Explanation:

Here are the details:

Mitch Marner's mass = 80 kg

Zdano Chara’s mass = 116 kg

Marner's speed prior to the collision = 10 m/s

According to the conservation of momentum, the sum of momentum before the collision equals the sum of momentum afterward:

m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂

Where;

m₁ = Mitch Marner's mass = 80 kg

m₂ = Zdano Chara's mass = 116 kg

u₁ = Mitch Marner's initial velocity = 10 m/s

u₂ = Zdano Chara's initial velocity = 0 m/s

v₁ = Mitch Marner's final velocity

v₂ = Zdano Chara's final velocity

Assuming a direct collision, both players will have an identical instantaneous velocity just after impact, thus;

v₁ = v₂ = v

The equation can be expressed as;

m₁×u₁ + m₂×u₂ = (m₁ + m₂) × v₂

Substituting the numbers gives;

80 × 10 + 116 × 0 = (80 + 116) × v = 196 × v

Which simplifies to;

80 × 10 + 116 × 0 = 196 × v

800 = 196 × v

Thus, v = 800/196 = 100/49 = 4\frac{4}{19} \ m/s

This means the final instantaneous velocity for both Marner and Chara is 4\frac{4}{19} \ m/s

The change in velocity for Marner = 10 - 4\frac{4}{19} = 5\frac{15}{19} \ m/s

The change in velocity for Chara = 4\frac{4}{19} - 0 = 4\frac{4}{19} \ m/s

Therefore;

1) Marner's velocity changes more significantly

2) The reason being her mass relative to the total mass of both is smaller than Chara's mass relative to their total mass

This indicates that Marner's velocity alteration exceeds that of Chara due to Marner's lower mass.

5 0
2 months ago
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