A colored dye compound decomposes to give a colorless product. The original dye absorbs at 608 nm and has an extinction coeffici
ent of 4.7 ×10⁴ M⁻¹cm⁻¹ at that wavelength.
You perform the decomposition reaction in a 1-cm cuvette in a spectrometer and obtain the following data:
Time (min) - Absorbance at 608 nm
0 - 1.254
30 - 0.941
60 - 0.752
90 - 0.672
120 - 0.545
From these data, determine the rate law for the reaction "dye → product" and determine the rate constant.
You perform the decomposition reaction in a 1-cm cuvette in a spectrometer and obtain the following data:
Time (min) - Absorbance at 608 nm
0 - 1.254
30 - 0.941
60 - 0.752
90 - 0.672
120 - 0.545
From these data, determine the rate law for the reaction "dye → product" and determine the rate constant.
You might be interested in
The visual representation is displayed in the following image.
For calculations, consider 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; this represents the mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; indicating the mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; this is the quantity of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; this is the quantity of carbon.
n(Cl): n(C) = 2.41 mol: 1.21 mol = 2: 1.
The compound in question is identified as dichlorocarbene CCl₂.
Answer:
The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
Comprehensive calculations are displayed in the attachment.
