As the plane heads toward Halifax, the wind speed supports the flight path
resulting in an overall improved speed
Conversely, during the return trip, the wind will resist the plane's motion, decreasing the net speed
The total journey lasts 13 hours
of which 2 hours was dedicated to the mathematics discussion
Consequently, the total flight time is 13 - 2 = 11 hours
Now we apply the formula to calculate the time for traveling to Halifax

Time needed to return

Let’s look at the total time


Here d = 3000 miles



By solving the derived quadratic equation

the plane's speed calculates to 550 mph
Answer:
The result is 0.750 NC
Explanation:
I am also taking the same test
The masses of particle A, B, and C are given, with all three particles aligned linearly. The distances between them are noted. The gravitational forces are attractive, compounding when acting in the same direction. The effects on each particle are formulated based on their distances.
Answer:
A)
denotes the resultant velocity of cart B post-collision.
B) 
C) 
D) 
E) 
F) Yes, kinetic energy remains conserved in this situation because both colliding bodies have identical mass.
G) Yes, momentum is conserved in every elastic collision.
Explanation:
Given:
- mass of car A,

- mass of car B,

- initial velocity of car A,

- final velocity of car A,

A)
The question mentions the cars experience an elastic collision:
By applying momentum conservation principles:


denotes the resulting velocity of cart B after collision.
B)
Initial kinetic energy of cart A:



C)
Initial kinetic energy of cart A:



D)
The final kinetic energy of cart A:



E)
The final kinetic energy of cart B:



F)
Yes, kinetic energy is conserved in this case due to both masses being identical in the collision.
G)
Indeed, momentum is consistently conserved in elastic collisions.
Answer:2.53*10^-10F
Explanation:
C=£o£r*A/d
Where £ represents the permittivity constant
£o= 8.85*10^-12f/m
£r=6.3
A=150mm^2=0.015m^2
d=3.3mm= 0.0033m
C=8.85*10^-12*6.3*0.015/0.0033
C=8.85*6.3*10^-12*0.015/0.0033
C=55.755*0.015^-12/0.003
C=8.36/3.3*10^-13+3
C=2.53*10^-10F