Respuesta:
11.4 m/s
Explicación:
La fórmula para la aceleración centrípeta es:

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.
En este problema,
a = g = aceleración debida a la gravedad en la cima = 
v = ?
R = 13.2 m
Por lo tanto,


v = 11.4 m/s
1. τbiceps = +(Positive)
2. τforearm = -(Negative)
3. τball = -(Negative)
Explanation:
The attached figure illustrates the following: 1. For the biceps, τbiceps indicates that torque is calculated as Torque = r x F, where r and F are vectors. Here, r corresponds to the vector from the elbow to the biceps. In the figure, the force from the biceps is directed upwards. Applying the right-hand rule from r to F results in counterclockwise torque, which is considered positive (+).
2. The torque related to the weight of the forearm, τforearm, uses the same torque formula, with r being the vector from the elbow to the forearm. The weight acts downward, causing a clockwise torque that is negative (-).
3. Similarly, for the weight of the ball, τball, the downward force from the ball's weight generates a clockwise torque, which also registers as negative (-).
Explanation:
The formula illustrating the relationship between resistance and temperature is as follows:
R =
![R_{o} + \alpha [T_{2} - T_{1}]](https://tex.z-dn.net/?f=R_%7Bo%7D%20%2B%20%5Calpha%20%5BT_%7B2%7D%20-%20T_%7B1%7D%5D)
where, R = final resistance
= initial resistance
= temperature coefficient of resistivity
= final temperature 
= initial temperature
Given data as follows.
R = 36 ohm,
= 3 ohm
= 0.0045
Substituting the provided values into the above formula gives us the following.
R = 
36 =
=
![3 + 0.0045 \times [T_{2} - 293]](https://tex.z-dn.net/?f=3%20%2B%200.0045%20%5Ctimes%20%5BT_%7B2%7D%20-%20293%5D)
= 7626.33 K
Thus, it can be concluded that
the temperature of the light bulb at 12.0 V is 7626.33 K.
Response: Numerous elements can be found, all situated within the same vertical column as bromine.
Explanation:
Elements are organized by their atomic numbers on the periodic table. Those in the same vertical column (known as groups) exhibit the same valence electron configurations, resulting in similar chemical characteristics. Consequently, there are numerous elements sharing analogous chemical properties grouped with Bromine.
Answer:
a) The frequency is 3.191x10^11.
b) The type of radiation is microwave radiation.
c) The energy of one quantum of this radiation amounts to 1.32x10^-3ev.
Explanation:
For further details and calculations, please refer to the image below.