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13 days ago

Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min

Physics

1 answer:

Softa [913]13 days ago

4 0

Answer: Option (A) is correct.

Explanation:

The momentum of the 0.04 kg car moving at 2.00 m/s is

$P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s$

The highest permissible speed for the other car to avoid breaking the eggs matches that of the first car:

$P_1=P_2$

$0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2$

$v_2=1 m/s$

Any velocity just above 1 m/s will raise the second car's momentum, causing the eggs to break. Therefore, the minimum speed required by the second car from the options given is 1.42 m/s.

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What is the number N0 of 99mTc atoms that must be present to have an activity of 15mCi?

Keith_Richards [1021]

Based on my findings, within a period of 2 hours, there are certain atoms remaining. N = N0 * 2^(-t/6.020) = N = N0 * 2^-0.33223 = 0.7943 N0 Thus, the quantity of atoms that undergo disintegration is N0 - N = N0 * (1 - 0.79430) = 0.2057 N0 This must equate to 15 mCi = 15 * 3.7 * 10^7 = 5.55 * 10^8 atoms N0 = 5.55 * 10^8 / 0.2057 = 2.698 * 10^9 atoms Consequently, 2.698 * 10^9 atoms represents the value of N0.

4 0

5 days ago

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

ValentinkaMS [1144]

Answer:

The equivalent distance in kilometers is 4012 × $10^{-6}$ km.

Explanation:

It's known that 1 millimeter converts to $10^{-3}$ meters. Then, 1 meter converts to $10^{-3}$ kilometers. Therefore, the conversion for 1 millimeter to kilometers can be stated as

1 mm = $10^{-3}$ m

1 m = $10^{-3}$ km

Thus, 1 mm = $10^{-3}$ × $10^{-3}$ km = $10^{-6}$ km.

Given the distance of 4012 mm, the corresponding distance in kilometers will be

4012 mm = 4012 × $10^{-6}$ km.

The distance therefore is 4012 × $10^{-6}$ km.

5 0

13 days ago

Two planets having equal masses are in circular orbit around a star. Planet A has a smaller orbital radius than planet B. Which

serg [1189]

Answer:

Explanation:

To approach this problem, we need to understand two key concepts.

First, the gravitational force on an object in orbit equals its mass multiplied by centripetal acceleration.

Secondly, Newton's law of universal gravitation defines the force between two masses: Fg = mMG/r², where Fg denotes gravitational force, m and M signify the masses, G represents the gravitational constant, and r indicates the distance separating the two masses.

Thus:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

Potential energy for each planet is expressed as:

PE = mgr = m (MG/r²) r = mMG/r

Kinetic energy for each planet is computed as:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

Total mechanical energy is calculated as:

ME = PE + KE = 3/2 mMG/r

Since both planets share the same mass, the only variable is their orbital radius. Consequently, Planet A, with a smaller radius, possesses greater potential, kinetic, and mechanical energy.

6 0

13 days ago

The spring in a retractable ballpoint pen is 1.8 cm long, with a 300 N/m spring constant. When the pen is retracted, the spring

Sav [1095]

Answer:

The pen requires 7.2 mJ of energy to extend.

Explanation:

Provided:

Length = 1.8 cm

Spring constant = 300 N/m

Initial compression = 1.0 mm

Additional compression = 6.0 mm

Total compression = 1.0 + 6.0 = 7.0 mm

We need to determine the energy needed

This energy is equivalent to the variation in spring potential energy

$E=PE_{2}-PE_{1}$

$E=\dfrac{1}{2}kx_{2}^2-\dfrac{1}{2}kx_{1}^2$

Substitute the values into the formula

$E=\dfrac{1}{2}\times300\times(7.0\times10^{-3})^2-\dfrac{1}{2}\times300\times(1.0\times10^{-3})^2$

$E=0.0072\ J$

$E=7.2\ mJ$

Therefore, a total of 7.2 mJ is needed to extend the pen.

7 0

11 days ago

Read 2 more answers

A long cylindrical rod of diameter 200 mm with thermal conductivity of 0.5 W/m⋅K experiences uniform volumetric heat generation

Ostrovityanka [942]

Answer:

a, 71.8° C, 51° C

b, 191.8° C

Explanation:

Given the data:

D(i) = 200 mm

D(o) = 400 mm

q' = 24000 W/m³

k(r) = 0.5 W/m.K

k(s) = 4 W/m.K

k(h) = 25 W/m².K

The heat generation formula can be articulated as follows:

q = πr²Lq'

q = π. 0.1². L. 24000

q = 754L W/m

Thermal conduction resistance, R(cond) = 0.0276/L

Thermal conduction resistance, R(conv) = 0.0318/L

Applying the energy balance equation,

Energy In = Energy Out

This equates to q, which is 754L

From the initial analysis, the temperature at the interface between the rod and sleeve is found to be 71.8° C

Additionally, the outer surface temperature records as 51° C

Furthermore, based on the second analysis, the calculated temperature at the center of the rod is determined to be 191.8° C

6 0

9 hours ago