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krek1111
4 months ago
7

Suppose a 0.04-kg car traveling at 2.00 m/s can barely break an egg. What is the min

Physics
1 answer:
Softa [3K]4 months ago
4 0

Answer: Option (A) is correct.

Explanation:

The momentum of the 0.04 kg car moving at 2.00 m/s is

P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s

The highest permissible speed for the other car to avoid breaking the eggs matches that of the first car:

P_1=P_2

0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2

v_2=1 m/s

Any velocity just above 1 m/s will raise the second car's momentum, causing the eggs to break. Therefore, the minimum speed required by the second car from the options given is 1.42 m/s.

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