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aniked
4 months ago
12

On a guitar, the lowest toned string is usually strung to the E note, which produces sound at 82.4 82.4 Hz. The diameter of E gu

itar strings is typically 0.0500 0.0500 in and the scale length between the bridge and nut (the effective length of the string) is 25.5 25.5 in. Various musical acts tune their E strings down to produce a "heavier" sound or to better fit the vocal range of the singer. As a guitarist you want to detune the E on your guitar to A# ( 58.3 58.3 Hz). If you were to maintain the same tension in the string as with the E string, what diameter of string would you need to purchase to produce the desired note? Assume all strings available to you are made of the same material.

Physics
1 answer:
Softa [3K]4 months ago
8 0

The entire and thorough solution is included.

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A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along
Softa [3030]

Answer:

v = \frac{kQ}{a}  

Explanation:

We define the linear charge density as:

\lambda = \frac{Q}{L}

     Where L is the length of the rod, in this scenario the semicircle's length is L = πr

The potential at the center created by a differential element of charge is:

dv = \frac{kdq}{r}

          where k denotes Coulomb's constant

                     r signifies the distance from dq to the center of the circle

Thus.

v = \int_{}^{}\frac{kdq}{a}  

v = \frac{k}{a}\int_{}^{}dq

v = \frac{kQ}{a}     The potential at the semicircle's center

4 0
2 months ago
A skateboarder is attempting to make a circular arc of radius r = 16 m in a parking lot. The total mass of the skateboard and sk
kicyunya [3294]

To address this question, we will utilize concepts linked to centripetal force, aligning it with the static frictional force acting on the object. Using this relationship, we can derive the velocity and input the known values. The defined values are:

r = 16m

m = 82kg

\mu_s = 0.63

The maximum velocity can be determined using centripetal force,

F_c = \frac{mv^2}{r}

Should be equal to,

\frac{mv^2}{r} = \mu_s mg

v = \sqrt{\mu_s gr}

v = \sqrt{(0.63)(9.8)(16)}

v = 9.93m/s

As a result, the highest speed achievable through the arc without slipping is 9.93m/s

3 0
3 months ago
If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?
serg [3582]

Answer:

2.5\cdot 10^{-4}

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

S=\frac{\Delta L}{L_0}

where

\Delta L indicates the alteration in length of the object

L_0 signifies the object's initial length

In this case, we have L_0 = 4 m and \Delta L=1 mm=0.001 m, hence the strain is

S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}


5 0
2 months ago
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