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aniked
1 month ago
12

On a guitar, the lowest toned string is usually strung to the E note, which produces sound at 82.4 82.4 Hz. The diameter of E gu

itar strings is typically 0.0500 0.0500 in and the scale length between the bridge and nut (the effective length of the string) is 25.5 25.5 in. Various musical acts tune their E strings down to produce a "heavier" sound or to better fit the vocal range of the singer. As a guitarist you want to detune the E on your guitar to A# ( 58.3 58.3 Hz). If you were to maintain the same tension in the string as with the E string, what diameter of string would you need to purchase to produce the desired note? Assume all strings available to you are made of the same material.

Physics
1 answer:
Softa [3K]1 month ago
8 0

The entire and thorough solution is included.

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The intensity level of a "Super-Silent" power lawn mower at a distance of 1.0 m is 100 dB. You wake up one morning to find that
Maru [3345]

Answer:

The correct option is 80 dB.

Explanation:

The transformation of sound intensity level into sound intensity utilizes the formula

[D] = 10 log (I/I₀)

Where I₀ = 10⁻¹² W/m²

[D] results in 100 dB

100 = 10 log (I/I₀)

Log (I/I₀) converts to 10

(I/I₀) = 10¹⁰

I is determined as I₀ × 10¹⁰ = 10⁻¹² × 10¹⁰ = 10⁻² W/m²

Sound intensity inversely relates to the square of the distance from the source.

I ∝ (1/d²)

I can be expressed as k/d²

When d = 1 m, the intensity is 10⁻² W/m²

Thus, 0.01 = k/1

Providing that k = 0.01 W

For d = 20 m, we can calculate I

I = 0.01/20² = 2.5 × 10⁻⁵ W/m²

With four neighbors mowing their lawns concurrently,

I = 4 × 2.5 × 10⁻⁵ = 10⁻⁴ W/m⁻²

The sound intensity level in decibels is represented as

[D] = 10 log (I/I₀)

[D] = 10 log (10⁻⁴/10⁻¹²)

[D] = 10 log (10⁸)

[D] = 10 × 8 = 80dB

4 0
1 month ago
Considering the activity series given for nonmetals, what is the result of the below reaction? Use the activity series provided.
ValentinkaMS [3465]

Response: The result would be no reaction.

Clarification:

7 0
1 month ago
Read 2 more answers
A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
serg [3582]
The result is 70.5 km/h. It seems the question is somewhat vague, but you're inquiring about the x-component of the helicopter's velocity. The x and y components can be calculated using sine and cosine ratios. The sine ratio connects the y-component with the overall velocity as follows: sin(angle) = y-component of velocity / velocity. Meanwhile, the cosine ratio relates the x-component to the velocity: cos(angle) = x-component of velocity / velocity. Given that you have both the angle and the velocity, and need to determine the x-component, you should apply the cosine ratio: cos(35°) = x-component / 86.0 km/h => x-component = 86.0 km/h * cos(35°) = 70.5 km/h.
6 0
21 day ago
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Now slowly begin to raise the temperature. At approximately what temperature would a heated material (metal, wood, etc.) begin t
ValentinkaMS [3465]
We will utilize Wien's displacement law, given by the equation λ T = b, where λ represents the wavelength of emitted light from a heated object at maximum. By substituting the provided temperature and constant b into the equation, we find λ for various temperatures: at 500 K, λ = 5.796 μm or 5796 nm; at 1050 K, λ = 2760 nm; at 1800 K, λ = 1610 nm; and at 2500 K, λ = 1159.2 nm. The visible light spectrum starts at 740 nm, suggesting that at 2500 K, some visible red light may emerge as its calculated peak wavelength is within the visible range.
3 0
18 days ago
Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc
ValentinkaMS [3465]

Answer:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

Explanation:

The four wires are arranged in series: this setup indicates that the same current passes through them, while the total voltage from the battery, V0, equals the combined voltages across each resistor:

V_0=V_1+V_2+V_3+V_4

Additionally, the total resistance for this series configuration is

R_{eq}=R_1+R_2+R_3+R_4

Using Ohm's law, we can determine the voltage V2 across wire 2:

V_2 = R_2 I (1)

Here, I represents the entire current flowing through the circuit, which is calculated as:

I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}

By substituting into equation (1), we derive V2:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

8 0
16 days ago
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