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6 days ago

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The magnitude of the force associated with the gravitational field is constant and has a value FF . A particle is launched from

point BB with an initial velocity and reaches point AA having gained U0U0 joules of kinetic energy. A resistive force field is now set up such that it is directed opposite the gravitational field with a force of constant magnitude 12F12F . A particle is again launched from point BB . How much kinetic energy will the particle gain as it moves from point BB to point AA ?

1 answer:

serg [1.1K]6 days ago

7 0

Answer:

The particle's kinetic energy will equal 12U₀.

Explanation:

Given that,

A particle is fired from point B with an initial speed and arrives at point A with U₀ joules of kinetic energy gained.

The consistent force acting is 12F.

As per the problem,

The kinetic energy is

$U_{0}=Fx$ ....(I)

Constant force remains at 12F.

A resistive force field now exists,

With the resistive force defined as,

$F_{r}=12F$

As the particle travels from point B to point A,

We need to find the kinetic energy

Using the kinetic energy formula

$U=F_{r}x$

Substituting values for $F_{r}$

$U=12Fx$

Then, from equation (I)

$U=12U_{0}$

Consequently, the particle’s kinetic energy will amount to 12U₀.

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Answer:

0.0984

Explanation:

The first diagram below illustrates a free body diagram that will aid in resolving this problem.

According to the diagram, the force's horizontal component can be expressed as:

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Substituting 42° for θ and 87.0° for $F$

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Meanwhile, the vertical component is:

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Again substituting 42° for θ and 87.0° for $F$

$F_Y =87.0 \ N \ *sin \ 42 ^\circ$

$F_Y =58.21 \ N$

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The magnitudes of both components are illustrated in the second diagram provided and can be represented as A cos θ and A sin θ

The frictional force can be expressed as:

$f = \mu \ N$

Where;

$\mu$ is the coefficient of friction

N = the normal force

Also, the normal reaction (N) is calculated as mg - F sin θ

Substituting $F_Y \ for \ F_{sin \ \theta}$ . Normal reaction becomes:

$N = mg \ - \ F_Y$

By balancing the forces, the horizontal component of the force equals the frictional force.

The horizontal component is described as follows:

$F_X = \mu \ ( mg - \ F_Y)$

Rearranging the equation above to isolate $\mu$ leads to:

$\mu \ = \ \frac{F_X}{mg - F_Y}$

Substituting in the following values:

$F_X \ = \ 64.65 \ N$

m = 73 kg

g = 9.8 m/s²

$F_Y = \ 58.21 N$

Thus:

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$\mu = 0.0984$

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A scientist is creating a new synthetic material. The material’s density is 6.1 g/cm3. Which sentences describe how the scientis

ValentinkaMS [1144]

Density is defined as the mass divided by the volume.

You can alter the density of a substance by adjusting either its mass or volume.

Increasing the volume while maintaining a constant mass will result in a decrease in density (as the denominator of the fraction increases).

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Therefore, to achieve a lower density, you should either reduce the mass or increase the volume, keeping the other constant.

I hope this is helpful.

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10 days ago

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Yuliya22 [1153]

Answer:

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Explanation:

Based on this,

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Answer:

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