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nata0808
2 months ago
11

An aluminum wire of length 1.0 meter has a resistance of 9.0x10^-3 ohm. If the wire were cut into two equal lengths, each length

would have a resistance of
Physics
2 answers:
Sav [3.1K]2 months ago
0 0

Answer: since resistance is influenced by length, the resistance will be equally distributed as the wire is cut into two equal parts, resulting in

4.5 * 10^-3 ohm.

Explanation:

kicyunya [3.2K]2 months ago
0 0

Answer: Each segment would have a resistance of 4.5\times 10^{-3}\Omega

Explanation:

Let the resistance of each half of the wire be denoted as r.

This means,

r+r=R

where,

r = resistance of one half of the wire.

R = total resistance of the full wire = 9.0\times 10^{-3}\Omega

Resistance is known to be directly proportional to the length of the wire.

Total resistance of the aluminum wire = Sum of resistances of the two cut pieces.

r+r=9.0\times 10^{-3}\Omega

2r=9.0\times 10^{-3}\Omega

r=\frac{9.0\times 10^{-3}\Omega}{2}

r=4.5\times 10^{-3}\Omega

Therefore, each length will have a resistance of 4.5\times 10^{-3}\Omega

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