An aluminum wire of length 1.0 meter has a resistance of 9.0x10^-3 ohm. If the wire were cut into two equal lengths, each length

Question

3 months ago

11

would have a resistance of

2 answers:

Sav [3.1K] · Answer 1 · 2026-02-15T22:41:33+03:00

Sav [3.1K]3 months ago

0 0

Answer: since resistance is influenced by length, the resistance will be equally distributed as the wire is cut into two equal parts, resulting in

4.5 * 10^-3 ohm.

Explanation:

kicyunya [3.2K] · Answer 2 · 2026-02-15T22:42:56+03:00

Answer: Each segment would have a resistance of $4.5\times 10^{-3}\Omega$

Explanation:

Let the resistance of each half of the wire be denoted as r.

This means,

$r+r=R$

where,

r = resistance of one half of the wire.

R = total resistance of the full wire = $9.0\times 10^{-3}\Omega$

Resistance is known to be directly proportional to the length of the wire.

Total resistance of the aluminum wire = Sum of resistances of the two cut pieces.

$r+r=9.0\times 10^{-3}\Omega$

$2r=9.0\times 10^{-3}\Omega$

$r=\frac{9.0\times 10^{-3}\Omega}{2}$

$r=4.5\times 10^{-3}\Omega$

Therefore, each length will have a resistance of $4.5\times 10^{-3}\Omega$