An aluminum wire of length 1.0 meter has a resistance of 9.0x10^-3 ohm. If the wire were cut into two equal lengths, each length
2 answers:
Answer: Each segment would have a resistance of
Explanation:
Let the resistance of each half of the wire be denoted as r.
This means,
where,
r = resistance of one half of the wire.
R = total resistance of the full wire =
Resistance is known to be directly proportional to the length of the wire.
Total resistance of the aluminum wire = Sum of resistances of the two cut pieces.
Therefore, each length will have a resistance of
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Answer:
Consequently, the temperature difference across the material will be
Explanation:
In this case, we apply the Fourier Law of heat conduction expressed by the following equation:
(1)
Where k = thermal conductivity = 0.2 W/ mK
A= 1m^2 denotes the cross-sectional area
Q= 3KW signifies the heat transfer rate
is the temperature difference we need to determine
represents the thickness of the material
Initially, we convert 3KW to W, resulting in:
With all variables accounted for, we can substitute and calculate:
Thus, the temperature difference across the material will be
Answer:
A) The updated amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please refer to the attached documents for the solution.
