Duane skis down a hill at an angle of 42°. He has a mass of 92 kg. What is the normal force on Duane?

Violet light (λ = 400 nm) passing through a diffraction grating for which the slit spacing is 6.0 μm forms a pattern on a screen

Maru [3345]

Answer:

The third-order dark fringe

Explanation:

y = Distance from central bright fringe = 204 mm

λ = Wavelength = 400 nm

L = Distance from screen to source = 1 m

d = Slit spacing = 6 μm

$tan\theta =\frac{y}{L}\\\Rightarrow tan\theta =\frac{204}{1000}=0.2012^{\circ}$

$dsin\theta=m\lambda\\\Rightarrow m=\frac{dsin\theta}{\lambda}\\\Rightarrow m=\frac{6\times 10^{-6}sin0.2012}{400\times 10^{-9}}=2.9982\approx 3$

The order of the fringe is 3

Thus, it’s identified as a dark fringe.

3 0

3 months ago

Two objects are maintained at constant temperatures, one hot and one cold. Two identical bars can be attached end to end, as in

inna [3103]

The ratio Qa/Qb is determined as k/2×2k, yielding a value of 1/4. In the scenario where situation 'a' embodies series and 'b' depicts parallel arrangements, the conductance for each plate is k. Thus, net conductance for series equals k/2, while for parallel it is 2k.

7 0

2 months ago

You're driving your pickup truck around a curve that has a radius of 22 m.How fast can you drive around this curve before a stee

Sav [3153]

The maximum speed around this curve before a toolbox made of steel slips off the truck bed is: 14.832 m/s

Further explanation

The centripetal force acts on objects in circular motion, directed towards the circle's center.

$\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}$

F = centripetal force, N

m = mass, Kg

v = linear velocity, m / s

r = radius, m

The velocity directed toward the center of the circle is referred to as linear velocity.

It can be represented as:

$\displaysyle v = 2 \pi.r.f$

r = radius of the circle

f = rotations per second (RPS)

Pickup trucks negotiating a curve are influenced by centripetal forces. To prevent the steel toolbox from slipping off the bed of the truck, the centripetal force acting on it must equal its weight. Should the centripetal force surpass the toolbox's weight, it will fall off.

centripetal force = weight

$\rm \dfrac{mv^2}{r}=mg$