This is quite an unusual scenario...:/ It all hinges on her weekly earnings. If she were to work 40 hours each week at $10 per hour, then she would have sufficient funds. Even if she were a student working part-time for 30 hours at $8 per hour, she would still accumulate enough.
Let’s determine the actual mean
First, we sum all the values
87+46+90+78+89 = 390
Then, we divide 390 by the count of numbers present.
390/5 = 78
Thus, the mean is 78
Emi did not manage to calculate the difference
Answer:

Step-by-step explanation:
Review the provided matrix
![A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D)
Let matrix B be defined as
![B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
It is stated that

![\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%263%5C%5C2%2617%260%5C%5C3%2622%268%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_%7B11%7D%26b_%7B12%7D%26b_%7B13%7D%5C%5Cb_%7B21%7D%26b_%7B22%7D%26b_%7B23%7D%5C%5Cb_%7B31%7D%26b_%7B32%7D%26b_%7B33%7D%5Cend%7Barray%7D%5Cright%5D)
By comparing the corresponding elements from both matrices, we derive



Consequently, the needed values are
.
Response:
The area of the shaded part is 42.50 cm².
Detailed explanation:
Examine the diagram provided.
The circle has a radius of r = 5 cm.
Dimensions of the rectangle are:
l = 11 cm
b = 11 cm.
Calculate the area of the shaded portion as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Consequently, the shaded area totals 42.50 cm².
The entire question can be found in the attached image.
It's clear that
[volume of a rectangular prism]=L*W*H
<span>Among the options provided, the highest is 100
</span>100>10
100>20
100>60
100>50
V=L*W*H
with V=100 in³ and L=100 in
100 in³=100*W*H----------> W*H=1
<span>Thus, to achieve a maximum length of 100, the multiplication of width and height must equal 1.
</span>
The response is
the option A) 100