Response:
4.5 m³
Resolution:
The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.
After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).
Hence, The data established is,
P₁ = 4 atm
V₁ = 9 m³
P₂ = 8 atm
V₂ =?
Using Boyle's Law,
P₁ V₁ = P₂ V₂
Resolving for V₂,
V₂ = P₁ V₁ / P₂
Substituting values yields:
V₂ = (4 atm × 9 m³) ÷ 8 atm
V₂ = 4.5 m³
Answer:
Ir(NO2)3
Explanation:
The molar mass is 330.2335, in case that's also required.
A. 1.01 is the accurate result
Because
The formula used is Pv= nRT
P=1 atm
V= 22.4 L
N= x
R= 0.0821
T= 273 K (since it’s standard temperature)
Thus, (1)(22.4)=(x)(0.0821)(273)
X= 1.001
