Calculate the molecular weights for nh3 and sf6

Which of the following statements is a true statement concerning a reaction that has reached a state of equilibrium?

KiRa [2933]

A system is considered at equilibrium when the concentrations of reactants and products stay constant over time. Reactions that do not reach completion, where reactants can form products while products can revert back to reactants simultaneously, are categorized as equilibrium reactions. The nature of equilibrium is dynamic, meaning reactions continue to occur, with the rate of the forward reaction equating to that of the reverse reaction. In this state, even though both reactants and products coexist, their concentrations do not vary.

8 0

2 months ago

The solubility of KCl is 3.7 M at 20 °C. Two beakers each contain 100. mL of saturated KCl solution: 100. mL of 4.0 M HCl is add

Tems11 [2777]

Answer:

a) The ion-product constant Ksp was determined to be 13.69

Explanation:

Terminology

The Qsp for an ionic solid dissolving reflects the solubility product of ions in solution.

Ksp, in contrast, defines the equilibrium state solubility product of these ions in solution when in balance with the dissolving solid.

It’s important to note that if Qsp exceeds Ksp at a particular temperature, precipitation will occur, causing the equilibrium to shift left to maintain balance (Ksp).

Steps to Solve:

To calculate this:

1. Replace the molar solubility of KCl into the ion-product equation to identify the Ksp of KCl.

2. Assess the total concentration of potassium chloride ions in each beaker after HCl has been added, taking into consideration initial moles and those added.

3. Calculate Qsp to determine whether it surpasses Ksp. If Qsp is below Ksp, no precipitation occurs.

Thus, the equilibrium equation for KCl can be expressed as:

KCL_(s) ---> K+(aq) + Cl- (aq)

The provided KCl solubility is 3.7 M.

Ksp= [K+][Cl-] = (3.7)(3.7) =13.69

Therefore, the Ksp was found to be equal to 13.69.

In pure water, KCl

Ksp =13.69 KCl =[K+][Cl-]

Let x represent the molar solubility [K+]/[Cl-]:. x, x

Ksp =13.69 = [K+][Cl-] = (x)(x) = x²

x= √ 13.69 = 3.7 M moles of KCl necessary for a 100mL saturated solution

37M moles/L

The Ksp was determined to be equal to 13.69.

4.0 M HCl = KCl =[K+][Cl-]

Let y signify the molar solubility:. y, y+4

Ksp =13.69= [K+][Cl-] = (y)(y*+4)

* - as a general guideline

Ksp =13.69= [K+][Cl-] = (y)(y*+4)= y(4)

13.69=4y:. y= 3.42 moles/100mL

y= 34.2moles/L

8 M HCl = KCl =[K+][Cl-]

Let b denote the molar solubility:. B, b+8

Ksp =13.69= [K+][Cl-] = (b)(b*+8)

* - as a general guideline

Ksp =13.69= [K+][Cl-] = (b)(b*+8)= b(8)

13.69=8b:. b= 1.71 moles/100mL

17.1 moles/L

Thus, in a solution containing a common ion, the compound's solubility significantly decreases.

8 0

2 months ago

Read 2 more answers

Which list of radioisotopes contains an alpha emitter, a beta emitter, and a positron emitter?

alisha [2963]

Answer: The correct option is 3.

Explanation: Radioisotopes that emit alpha-particles are termed alpha-emitters. These isotopes undergo alpha-decay.

Those radioisotopes that emit beta-particles $(_{-1}^0\beta )$ are called beta-emitters. They undergo beta-minus decay, in which a neutron converts to a proton and an electron.

Isotopes that emit positrons $(_{+1}^0\beta )$ are known as positron-emitters, undergoing beta-plus decay where a proton becomes a neutron.

From the options given,

Option 1: All three isotopes undergo beta-minus decay.

Option 2: Cs-137 and Tc-99 undergo beta-minus decay.

Fr-220 undergoes alpha-decay.

Option 3: Kr-85 undergoes beta-minus decay.

$_{36}^{85}\textrm{Kr}\rightarrow _{37}^{85}\textrm{Rb}+_{-1}^0\beta$

Ne-19 undergoes positron decay.

$_{10}^{19}\textrm{Ne}\rightarrow _{9}^{19}\textrm{F}+_{+1}^0\beta$

Rn-222 undergoes alpha decay.

$_{86}^{222}\textrm{Rn}\rightarrow _{84}^{218}\textrm{Po}+_{2}^4\alpha$

Option 4: All three isotopes undergo beta-minus decay processes.

Therefore, the correct choice is 3.

6 0

2 months ago

Read 2 more answers

Approximately 220 million tires are discarded in the U.S. each year. These tires present a disposal problem because they take up

lions [2927]

Answer:

A total of 2667 tires are required to satisfy the annual power needs of ten homes.

Explanation:

According to the Second Law of Thermodynamics, not all energy produced when tires are incinerated can be effectively used due to losses associated with finite temperature differences. The energy obtainable from a tire when burned, measured in kilowatt-hours ( $E_{out}$ ), can be calculated using the efficiency definition: