Carbon dioxide readily absorbs radiation with an energy of 4.67 x 10-20 J. What is the wavelength and frequency of this radiatio

Question

1 month ago

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n? Does this radiation fall in the ultraviolet, visible, or infared range?

1 answer:

Tems11 [2.7K] · Answer 1 · 2026-02-23T19:42:20+03:00

Answer:

ν = 7.04 × 10¹³ s⁻¹

λ = 426 nm

This wavelength is included in the visible spectrum.

Explanation:

The connection between the energy of radiation and its frequency is expressed through the Planck-Einstein equation:

E = h × ν

where,

E represents energy

h refers to the Planck constant (6.63 × 10⁻³⁴ J.s)

ν is the frequency

Next, we can determine the frequency,

$\nu = \frac{E}{h}= \frac{4.67 \times 10^{-20}J }{6.63 \times 10^{-34}J.s} = 7.04 \times 10^{13} s^{-1}$

Frequency and wavelength are interconnected via the subsequent equation:

c = λ × ν

where,

c indicates the speed of light (3.00 × 10⁸ m/s)

λ signifies the wavelength

$\lambda = \frac{c}{\nu } =\frac{3.00 \times 10^{8} m/s }{7.04 \times 10^{13} s^{-1} } =4.26 \times 10^{-6}m.\frac{10^{9}nm }{1m} = 426 nm$

A wavelength of 426 nm is found within the visible range (approximately 380-740 nm)