The answer is D. Aluminium Oxide 0.10, Magnesium Oxide 0.50. Firstly, for sodium hydroxide, we can calculate the number of moles using the formula moles = concentration × volume, leading to 0.2 moles from 100 cm³ at 2 moldm-3. Since 2 moles of NaOH yield 1 mole of Al2O3, this means 0.2 moles of NaOH produces 0.1 moles of Al2O3. For hydrochloric acid, moles can similarly be determined, leading to 1.6 moles from 800 cm³ at 2 moldm-3. Considering that 1 mole of Al2O3 reacts with 6 moles of HCl, 0.1 moles of Al2O3 will consume 0.6 moles of HCl. Post-reaction, we have 1 mole of HCl remaining, which will further react with magnesium oxide, thereby yielding 0.5 moles of MgO.
Answer:
The work done in this process will be considered Negative.
Explanation:
The energy transferred by the system to the environment is negative
Therefore, if work is done on the system, it is labeled as positive. Conversely, when work is done by the system, it is regarded as negative.
In this scenario, the argon gas is expanding, and the work is exerted by the system into the surroundings (container), making the sign Negative.
Thus, the result for the work pertaining to this process will carry a Negative sign.
1. Saturated hydrocarbons can either be cyclic or acyclic structures. 2. An unsaturated hydrocarbon molecule contains at least one double bond. Explanation: Greetings, hydrocarbons are defined as the most basic organic compounds comprising only carbon and hydrogen. Therefore, we can eliminate the third statement since ethylenediamine is identified as an amine (an organic structure containing NH groups). Consequently, as saturated hydrocarbons only exhibit single bonds between carbons and carbon-hydrogens, they may be cyclic (ring-shaped) or acyclic (not ring-shaped), establishing the truth of the first statement. Finally, since saturated hydrocarbons exclusively feature single bonds while unsaturated hydrocarbons can exhibit double or triple bonds between carbons and carbon-hydrogens, the existence of at least one double bond categorizes the hydrocarbon as unsaturated. Hence, the first two statements are correct. Best regards.
