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goldenfox
6 days ago
10

For the given functions f (x), let x0 = 0, x1 = 0.6, and x2 = 0.9. construct interpolation polynomials of degree at most one and

at most two to approximate f (0.45), and find the absolute error

Mathematics
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The yearly cost in dollars, y, for a member at a video game arcade based on total game tokens purchased, x, is y =y equals Start
Leona [12618]

Response:

y = \frac{1}{5}x

Step-by-step explanation:

Given data:

Annual cost for members: y = \frac{1}{10}x + 6

Required:

Calculate the yearly expense for non-members

From the context, we infer that:

A non-member pays $0.20 per game;

Annual cost can be determined using the formula;

y = Amount * Number of Games

Where:

Amount = $0.2, Number of Games = x

y = 0.20 * x

Convert 0.2 to a fraction:

y = \frac{2}{10} * x

Divide the numerator and denominator by 2:

y = \frac{1}{5} * x

y = \frac{1}{5}x

Therefore, the yearly expense for non-members is

y = \frac{1}{5}x

6 0
3 months ago
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In the Ma-and-Pa grocery store, shelf-space is limited and must be used effectively to increase profit. Two-cereal items, Grano
Inessa [12570]
No. Allocate 2/3 of the space to Grano and 1/3 to Wheatie. This results in approximately 57% for Wheatie and 43% for Grano—meaning 60(.57)=34.2 ft² for Wheatie and 60(.43)=25.8 ft² for Grano. Therefore, there would be about 85.5 boxes of Wheatie and 129 boxes of Grano, leading to a total profit of 129(1)+85(1.35)=$243.75. The best choice would be to place 200 boxes of Grano and 50 boxes of Wheaties on the shelf. Allocating 40 ft² to Granos (200(.2)) and 20 ft² to Wheaties (50(.4)) means that 40/60=2/3=66.6% of the space would be for Granos, and 20/60=1/3=33.3% would be for Wheaties. The total profit would be 200(1)+50(1.35)=$267.5.
5 0
2 months ago
9. The purpose of statistical inference is to provide information about the.
AnnZ [12381]
<span>c. demographics based on the details in the population.#9

#10</span><span>b. 81 and 18.</span>
6 0
2 months ago
Tran has a credit card with a spending limit of $2000 and an APR (annual percentage rate) of 12%. During the first month, Tran c
babunello [11817]

Detailed explanation:

Information provided:

Tran possesses a credit card that allows up to $2000 in spending with an APR of 12%.

In the initial month, Tran incurred charges of $450 and settled $150 within that billing period.

The formula to determine the interest that will accrue for Tran in the first month is (0.012)(300)

Here, 0.01 signifies the monthly interest rate.

The 300 reflects the outstanding balance, as Tran charged $450 but only paid back $150.

5 0
2 months ago
A 16\dfrac1216 2 1 ​ 16, start fraction, 1, divided by, 2, end fraction kilometer stretch of road needs repairs. Workers can rep
lawyer [12517]

Answer:

The repair of the stretch of road will require

weeks to finish.7\frac{1}{3}

Step-by-step explanation:

Provided:

Length of the roads needing repair =

Length of the road workers can fix in a week = 16\frac{1}{2}\ km

To ascertain how many weeks it will take to mend this road stretch.2\frac{1}{4}\ km

Solution:

Worker's road repair rate =   per week.

Overall road length to repair =

2\frac{1}{4}\ km

The time required to repair 16\frac{1}{2}\ km

of road by the workers can be calculated: 16\frac{1}{2}\ km⇒

When dividing mixed numbers, we change them first into fractions.\frac{16\frac{1}{2}\ km}{2\frac{1}{4}\ km}

To compute fraction division, we take the reciprocal of the divisor and substitute division with multiplication:

⇒  \frac{\frac{33}{2}} {\frac{9}{4}}

We revert the fraction back into a mixed number.

Thus, it will take

weeks to complete the road repair task.\frac{33}{2}\times \frac{4}{9}

7 0
2 months ago
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