A cell was prepared by dipping a Cu wire and a saturated calomel electrode into 0.10 M CuSO4 solution. The Cu wire was attached

to the positive terminal of a potentiometer and the calomel electrode was attached to the negative terminal.(a) Write a half-reaction for the Cu electrode. (Use the lowest possible coefficients. Omit states-of-matter.)
(c) Calculate the cell voltage.

Chemistry

You might be interested in

Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi

VMariaS [2998]

Answer:

The revised net worth rounded to three significant figures is $80.2 billion.

The donation to charity amounts to $100,250,000.

Explanation:

Initial net worth is $77.0 billion.

Stock gains are $3.20 billion.

Calculating new net worth: $77.0 billion + $3.20 billion = $80.20 billion.

Hence, new net worth to three significant figures is $80.2 billion.

One-eighth of a percent is calculated as (1/8 x 1) / 100 = 0.00125.

The charitable contribution amounts to 0.00125 X $80.2 billion = $100,250,000.

Alternatively, $80,200,000,000 divided by 100 results in $802,000,000.

3 0

4 months ago

In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OAT

lorasvet [2795]

Answer: Reaction 2 is a spontaneous one.

Explanation:

According to our understanding:

$\Delta G$ = +ve, meaning the reaction is non-spontaneous

$\Delta G$ = -ve, indicating the reaction is spontaneous

$\Delta G$ = 0, stating that the reaction is at equilibrium

For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.

Reaction 1:

Glucose + Pi ⟶ glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol $\rightarrow$

Reaction 2:

ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol $\rightarrow$

From this, we can conclude that ΔG being negative indicates that reaction 2 is indeed spontaneous.

8 0

2 months ago