Noble gas notation serves as a condensed form of indicating electron configurations. This notation employs the symbol for the preceding noble gas in the electron configuration of an element. For antimony, the noble gas prior is Kr, which means Xe is not used in its electron configuration. Similarly, for radium, the prior noble gas is Rn, whereas, for uranium, it is also Rn. However, for cesium, the preceding noble gas is Xe, thus it is utilized in the noble gas notation for Sb, specifically written as: Cs: [Xe] 6s.
Answer: cesium
The electronic configuration of an atom details how electrons are organized across various shells and sublevels.
There are four categories of sublevels: s, p, d, and f. Each of these sublevels contains orbitals, which are regions with a high likelihood of containing an electron, with each orbital capable of holding a maximum of 2 electrons.
As a result,
s-sublevel possesses 1 orbital, allowing for a maximum of 2 electrons.
p-sublevel has 3 orbitals, accommodating a maximum of 6 electrons.
d-sublevel encompasses 5 orbitals, permitting a maximum of 10 electrons.
f-sublevel includes 7 orbitals, with a maximum of 14 electrons.
Therefore, the ascending order of sublevels based on the maximum number of electrons they can hold is:
s < p < d < f
<span>The condensation on the mirror occurs when water vapor contacts a chillier surface. When you let cold water run, the surroundings become cooler. Consequently, the steam generated from the hot shower primarily condenses nearby and doesn’t reach the mirror.</span>
Answer:
Explanation:
The percent composition indicates the mass percentage of a specific element within the compound.
The chemical formula for chromium(III) nitrate is 
.
The molar mass for chromium(III) nitrate is calculated at 238.011 g/mol.
Each mole of chromium(III) nitrate includes 9 moles of oxygen.
The molar mass of oxygen is 16 g/mol.
Hence, Mass = Molar mass * Moles = 16 * 9 g = 144 g.
Calculation yields 209.53. The molar concentration is calculated by moles divided by volume. Given the volume of 750 mL, which translates to 0.75 L, the moles of CuBr₂ can be determined as molar concentration multiplied by volume, resulting in 1.25 × 0.75 = 0.9375. Mole count is derived from the mass of CuBr₂ divided by its molecular mass. The molecular mass of CuBr₂ is computed as 63.5 + 80 × 2 = 223.5, where the mass of Cu is 63.5 and that of Br is 80. Consequently, the mass needed amounts to 223.5 × 0.9375 = 209.53 g.
