Answer:
Competitive forces model
Explanation:
The Competitive forces model is a crucial instrument in strategic analysis aiming to assess an organization’s competitiveness. Commonly referred to as the "Five Force Model of Porter", this framework includes five key factors: the intensity of rivalry among existing competitors, the negotiating power of buyers, the threat posed by potential new entrants, the bargaining strength of suppliers, and the risk of substitute products or services.
These elements significantly influence an organization's competitive strategy and its likelihood of success.
Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.
Explanation:
Let Q be the speed of the boat, and P be the speed of the river flow.
R represents the resultant velocity combining boat velocity and river current.
According to vector addition using the law of triangles:
From the diagram:
P = 3.5 km/h, Q = 4.5 km/h
Therefore, her velocity magnitude relative to the shore is 5.70 km/h.
Answer:
Explanation:
For a 60W light bulb used for 1 minute:
P = 60 W
t = 1 minute = 60 seconds
This energy is capable of lifting an object weighing 10N.
W = 10N
This indicates conversion of electrical energy into potential energy.
Let's calculate the electrical energy:
Power describes the rate of work done.
Power = Work / time
Thus, work = power × time
Work = 60 × 60
Work = 3600 J
Potential energy calculation:
P.E = mgh
Where the weight is given by:
W = mg
Therefore, P.E = W·h
P.E = 10·h
Thus, we equate:
Potential energy = Electrical energy
P.E = Work
10·h = 3600
Dividing both sides by 10 gives:
h = 3600 / 10
h = 360m
The object can be lifted to a height of 360m.
assuming north-south is along the Y-axis and east-west along the X-axis
X = total X-displacement
from the graph, total displacement in the X-direction is computed as
X = 0 - 20 + 60 Cos45 + 0
X = 42.42 - 20
X = 22.42 m
Y = total Y-displacement
from the graph, total displacement in the Y-direction is computed as
Y = 40 + 0 + 60 Sin45 + 50
Y = 90 + 42.42
Y = 132.42 m
To calculate the magnitude of the net displacement vector, we apply the Pythagorean theorem, yielding
magnitude: Sqrt(X² + Y²) = Sqrt(22.42² + 132.42²) = 134.31 m
Direction: tan⁻¹(Y/X) = tan⁻¹(132.42/22.42) = 80.4 deg north of east
Answer:
F=126339.5N
Explanation:
To compute the force required to escape, a free-body diagram for the hatch must be drawn. We will equate the downward and upward forces, thus applying the following equation:
Fw=W+Fi+F
where
Fw= force or weight exerted by the water column above the submarine.
To calculate Fw, we can use:
Fw=h. γ. A
h=height
γ=
specific weight of seawater = 10074N / m ^ 3
A=Area
Fw=28x10074x0.7=197467N
w represents the hatch weight = 200N
Fi denotes the internal pressure force in the submarine, which is 1 atm = 101325Pa. We can calculate this force using:
Fi=PA=101325x0.7=70927.5N
Finally, the force needed to open the hatch is determined by the original equation:
Fw=W+Fi+F
F=Fw-W+Fi
F=197467N-200N-70927.5N
F=126339.5N
