Initially, we convert the given radius of the wheel into meters, resulting in 0.325 m. Next, we compute the circumference.
C = 2πrr
By inserting the values,
C = 2π(0.325 m) = 2.04 m
Given a distance of 40 m for the road, we calculate the total number of complete revolutions as follows:
n = 40/2.04 m = 20.
Solution:
We know, g(x) = f(x) + k --------(1)
It is given that f(x) =
(x+2)
and g(x) =
(x+5)
Substituting f(x) and g(x) into equation (1):
→
(x+5) =
(x+2) + k
→
= k
→ k = 
Thus, the value of k is 1.