Answer:
This flowering plant population is in Hardy-Weinberg equilibrium.
Step-by-Step Explanation:
Initial population size = 60
Since both subpopulations are homozygous, allele frequencies are:
p = 80/120 = 0.66
q = 40/120 = 0.33
Expected genotype frequencies at equilibrium:
p² = 0.4356
2pq = 0.4356
q² = 0.1089
In a population of 420 plants, expected numbers are:
Homozygous dominant: 185 plants
Heterozygous: 185 plants
Homozygous recessive: 50 plants
Chi-square test:
Observed counts: red (178), pink (190), white (52)
Expected counts: red (185), pink (185), white (50)
Calculations:
Red: (178 - 185)² / 185 = 0.26
Pink: (190 - 185)² / 185 = 0.135
White: (52 - 50)² / 50 = 0.08
Total chi-square = 0.474
With 2 degrees of freedom, this chi-square corresponds to a p-value between 0.7 and 0.8, indicating no significant difference.