For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) 2A(aq)+3B(g)+C(l)↽−−⇀2D(s)+3E(g) th
e concentrations and pressures at equilibrium are [ A ] = 5.66 × 10 − 2 M [A]=5.66×10−2 M , P B = 5.69 × 10 3 Pa PB=5.69×103 Pa , [ C ] = 9.14 M [C]=9.14 M , [ D ] = 15.78 M [D]=15.78 M , and P E = 9.33 × 10 4 torr PE=9.33×104 torr . Calculate the thermodynamic equilibrium constant, K K .
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Answer: The correct selection is (b).
Explanation:
The energy required to detach an electron from an atom or ion in its gaseous state is termed ionization energy.
This indicates that a smaller atom necessitates a greater amount of energy to remove its valence electron. The reason for this is that there exists a strong attraction between the nucleus and the electrons in smaller atoms or elements.
Therefore, a significant amount of energy is needed to dislodge the valence electrons.
The electronic configuration for helium is . Hence, due to its fully occupied valence shell, it exhibits greater stability.
Consequently, a large amount of energy is needed to remove an electron from a helium atom.
In conclusion, from the choices provided, the ionization energy of helium will be greater than that of the diatomic molecule.