A 10.0 mL 10.0 mL aliquot is removed from the described stock solution and diluted to a total volume of 100.0 mL. 100.0 mL. Calc

Answer:

The molality is 1.15 m.

Molality is calculated by dividing the number of moles of solute by the kilograms of solvent, which in this case is water.

Calculate moles of H₂SO₄ from molarity:

C = n/V → n = C × V = 6.00 mol/L × 0.048 L = 0.288 moles

Mass of solvent (water) based on density:

m = ρ × V = 1.00 kg/L × 0.250 L = 0.250 kg

Therefore, molality is:

m = moles/solvent mass = 0.288 moles / 0.250 kg = 1.15 m

Answer:

710.33 g NO2

Explanation:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O  

(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 utilized for combusting octane

= 15.44 mol O2 used for generating NO2

O2 + 2NO → 2NO2

(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710.33 g NO2

Answer:

6

Explanation:

H6 indicates the presence of helium atoms, with 6 representing their quantity.

Response:

            A covalent bond is formed when the outer electrons of two atoms are shared, enabling them to adequately fill their orbitals.

Clarification:

                   Covalent bonds occur between atoms with an electronegativity difference below 1.7. In this bonding type, one atom's valence electrons create a molecular bond with the other atom's valence electrons, leading to mutual sharing of electrons.

                   Covalent bonds can be non-polar, as seen in hydrogen and carbon bonding.

                   Conversely, covalent bonds can also be polar, such as the bond between hydrogen and chlorine, where the chlorine atom is more electronegative and draws electrons towards itself, resulting in a lower electron density on the hydrogen atom.