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13 hours ago

A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain

store want the oversize version.
a. among ten randomly sleected customers whowant this type of racket, what is the
probability that at least six want theoversize version?
b. Among ten randomly selected customers,what is the probability that the number who want the oversizeversion is within i standard deviation of the mean value?
c. The store currently has seven rackets ofeah version. What is the probability that all of the next tencustomers who want this racket can get the version they want fromcurrent stock?

Mathematics

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Which are the roots of the quadratic function f(b) = b2 – 75? Select two options. b = 5 StartRoot 3 EndRoot b = Negative 5 Start

zzz [12365]

Answer:

b = 5√3

b = -5√3

Step-by-step explanation:

We have

$f(b)=b^{2}-75$

Keep in mind, the root of a function corresponds to the value of x at which the function's output is zero.

In this case

The roots of the equation are the b values for which f(b) equals zero.

Thus

For f(b)=0

$b^{2}-75=0$

$b^{2}=75$

Take the square root of both sides

$b=(+/-)\sqrt{75}$

Now simplify

$b=(+/-)5\sqrt{3}$

$b=5\sqrt{3}$ and $b=-5\sqrt{3}$

So we find that

b = 5√3

b = -5√3

8 0

3 months ago

Read 2 more answers

In a test of a printed circuit board using a random test pattern, an array of 16 bits is equally likely to be 0 or 1. Assume the

AnnZ [12381]

Answer:

A), B), and C) are clarified below.

Step-by-step explanation:

The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.

Simplifying gives us

P[k] = nCk / 2^n

A. Probability of all bits being 1s

16c16/2^16 = 1/65536

B. Probability of all bits being 0s

16c0/2^16 = 1/65536

C. The probability of having exactly 8 bits as 1s and the other 8 as 0s

16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%

8 0

3 months ago