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Hoochie
7 hours ago
15

William and 5 friends each bought 4 baseball cards. They now have a total of 54 cards. How many cards did each person initially

have?
Mathematics
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What is the future value of $845 a year for seven years at an interest rate of 11.3 percent? $6,683.95 $6,075.69 $8,343.51 $8,00
lawyer [12517]
To determine the future value of an initial amount of $845 at an interest rate of 11.3% over 7 years, we will utilize the compound interest formula, which is expressed as:
A=p(1+r/100)^n
where:
A=future value
r=rate=11.3%=0.113
time=7 years
Hence, the future value of the capital will be:
A=845(1+0.113)^7
A=845(1.113)^7
A=$1,787.82 
7 0
2 months ago
Read 2 more answers
In how many ways can you receive four cards of the same face value and one card from the other 48 available cards?
Zina [12379]
A deck contains 13 groups of 4 cards, indicating 13 unique ways to select four cards sharing the same face value. Any subsequent card drawn will necessarily represent a different face value. Consequently, the total combinations for selecting 5 cards—4 of which share the same face value and 1 diverging—amount to 13 x 48.

13 x 48 = 624.


5 0
2 months ago
A silent auction was held for a quilt donated for charity. Fifteen bids that were drawn randomly are listed here. What percentil
Leona [12618]

The provided values are

$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155

To start, we will arrange these in ascending order

resulting in

$60 $85 $95  $105  $120  $145 $155 $175 $190 $215 $235 $240 $260 $285 $315

The total count is 15

the position of 105 is 4

Now, we can calculate the percentile

=\frac{4}{15} *100

Thus, the percentile for the bid of $105 is 26.667%...........Response

7 0
2 months ago
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Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro
AnnZ [12381]

|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%

8 0
2 months ago
Read 2 more answers
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