A farsighted girl has a near point at 2.0 m but has forgotten her glasses at home. The girl borrows eyeglasses that have a power

Answer:

1.5 m/s²

Explanation:

Begin by sketching a free body diagram.  Three forces are at play on the sea lion: the force of gravity acting downwards, the normal force that is perpendicular to the ramp, and the frictional force parallel to the ramp.

Considering the forces perpendicular to the incline:

∑F = ma

N − mg cos θ = 0

This gives us N = mg cos θ

Next, examining the forces parallel to the incline:

∑F = ma

mg sin θ − Nμ = ma

Substituting for N yields:

mg sin θ − (mg cos θ) μ = ma

g sin θ − g cos θ μ = a

hence a = g (sin θ − μ cos θ)

If we set θ = 23° and μ = 0.26:

a = 9.8 (sin 23 − 0.26 cos 23)

this results in a = 1.48

When rounded to two significant figures, the acceleration of the sea lion is 1.5 m/s².

Response:

The resistivity can be expressed as

Clarification:

According to the information provided,

    The value of the electric field measures  

     The density of current is given as  

Typically, resistivity is represented in mathematical terms as

by inserting values

Answer:

The convergence of light rays redirects them toward the focal point, resulting in a magnifying effect.

Explanation: