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stiv31
20 days ago
7

En una determinación cuantitativa se utilizan 17.1 mL de Na2S2O3 0.1N para que reaccione todo el yodo que se encuentra en una mu

estra que tiene una masa de 0.376 g. Si la reacción que se lleva a cabo es: I2 + 2Na2S2O3 → 2NaI + Na2S4O6 ¿Cuál es la cantidad de yodo en la muestra?En una determinación cuantitativa se utilizan 17.1 mL de Na2S2O3 0.1N para que reaccione todo el yodo que se encuentra en una muestra que tiene una masa de 0.376 g. Si la reacción que se lleva a cabo es: I2 + 2Na2S2O3 → 2NaI + Na2S4O6 ¿Cuál es la cantidad de yodo en la muestra?
Chemistry
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Given the connection between Aw and K (Aw=2k) could you use the ideal gas law and derive the Boltzmann constant. Water freezes a
lions [2927]

Answer:

Explanation:

The relationship between the new temperature scale and the absolute temperature scale is defined as follows

Aw = 2 K

for K = 273.15 (the freezing point of water on the absolute scale)

Aw = 2 x 273.15 = 546.3 K

Each division of the new scale is equivalent to half that of each division on the absolute scale

each division of the new scale is minimal.

The value of R = 8.314 J per mole per K

Here, per K corresponds to 2Aw

Hence, the value of R in the new scale = 8.314/2 J per mole per Aw

= 4.157 J per mole per Aw

k = R / N

= 4.157 / 6.02 x 10²³

= .69 x 10⁻²³

= 6.9 x 10⁻²⁴ J per molecule per Aw .

7 0
4 months ago
Read 2 more answers
15 g of gold and 25 g of silver are mixed to form a single-phase ideal solid solution.
Anarel [2989]
1. The total moles of the solution is 0.3079193 mol. 2. The mole fraction for gold is 0.2473212, and for silver, it is 0.7526787. 3. The molar entropy of mixing for gold is 2.87285 j/K, while for silver, it is 1.77804 j/K. 4. The total entropy of mixing sums to 4.65089 j/K. 5. Molar free energy amounts to -2325.445 kJ. 6. Chemical potential for silver is -1750.31129 j/mol and for gold, it is -575.13185 j/mol. To elaborate: (1) The molar mass of silver stands at 107.8682 g/mol, and gold's at 196.96657 g/mol. Hence, calculating moles leads to mass/molar mass for silver: 25 g/107.8682 g/mol = 0.2317643 mol and for gold: 15 g/196.96657 g/mol = 0.076155 mol, resulting in a total of 0.30791193 mol. (2) For the mole fractions, silver's fraction is 0.2317643/0.3079193 = 0.7526787, and for gold, it's 0.076155/0.3079193 = 0.2473212. (3) To find molar entropy mixing ∆Sm, we use the formula ∆Sm = -R * Xi * ln(Xi) where R = 8.3144598. For silver, substituting gives us 1.77804 j/K, while for gold, we get 2.87285 j/K. (4) Overall entropy of mixing totals 4.65089 j/K thus calculated. (5) The Gibbs free energy at 500 °C can be derived through G = H - TS, accounting to H = 0 (as T is 500 + 273 = 773 K and S is 4.65089), resulting in G equating to -3595.138 kJ. (6) The chemical potentials calculated derive from multiplying the Gibbs free energy by their mole fractions.
8 0
2 months ago
What type of ossification occurs to form an immovable joint
Tems11 [2777]
The form of ossification that takes place is the endomembrane or endochondral type. In joints classified as SYNARTROSIS, there isn't an intermediate formation of ligament or cartilage, meaning the bone grows not from cartilage ossification but from undifferentiated cells that will calcify into bone cells, forming the primary structural units called OSTEONAS. The skull bones, particularly in the temporal region (Temporary Suture), exhibit this type of joint, which experiences rapid growth over a lifetime through mechanisms distinct from those affecting movable joints.
5 0
3 months ago
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