How would one convert 6 lb to ounces (16oz = 1 lb)?

Answer:

Explanation:

In KCl, the two elements that combine to create KCl are potassium (K) and chlorine (Cl).

Potassium, as a Group 1 element, possesses one valence electron in its outermost shell which it readily donates during bonding. Every element aims to achieve a stable electron configuration, typically with 2 or 8 electrons in its outer shell. Potassium is characterized by its lower electronegativity and higher ionization energy, making it more likely to donate its electron than to accept one. On the other hand, chlorine belongs to Group 17 and has 7 electrons in its outer shell, requiring just one additional electron to complete its octet. Chlorine’s higher electronegativity and lower ionization energy facilitate its tendency to accept an electron rather than donate it.

The bond between potassium and chlorine that results in KCl is termed an electrovalent bond.

Reaction equation:

K + Cl → KCl

84.34 grams of iron (III) chloride is the maximum produced since iron is the limiting reagent, and chlorine gas is in excess.

Explanation:

Balanced equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA PROVIDED:

iron =  atoms

mass of chlorine = 67.2 liters

mass of FeCl3 =?

The number of moles of iron will be calculated as

number of moles =

number of moles =

number of moles = 0.52 mol of iron

moles of chlorine gas

number of moles =

Substituting the values into the equation:

n =               (molar mass of chlorine gas = 70.96 g/mol)

   = 947.01 moles

As iron is the limiting reagent therefore

2 moles of Fe lead to 2 moles of FeCl3

0.52 moles of Fe will yield

=

0.52 moles of FeCl3 is produced.

To express this in grams:

mass = n x molar mass

         = 0.52 x 162.2                   (molar mass of FeCl3 is 162.2g/mol)  

          = 84.34 grams        

⁴⁰Ar
N(e)=18
N(p)=18
N(n)=40-18=22

⁴⁰K
N(e)=19
N(p)=19
N(n)=40-19=21

⁴⁰Ca
N(e)=20
N(p)=20
N(n)=40-20=20

Answer:

pH = 8.0

Explanation:

Initially, we need to determine the moles of NaOH.

Consider the balanced reaction.

C₂H₄O₃ + NaOH ⇒ C₂H₃O₃Na + H₂O

The molar ratio among C₂H₄O₃, NaOH, and C₂H₃O₃Na is 1: 1: 1. Therefore, if 7.2 × 10⁻⁴ moles of NaOH completely react with 7.2 × 10⁻⁴ moles of C₂H₄O₃, they will yield 7.2 × 10⁻⁴ moles of C₂H₃O₃Na.

To find the concentration of C₂H₃O₃Na, we note that:

C₂H₃O₃Na dissociates as follows:

C₂H₃O₃Na(aq) ⇒ C₂H₃O₃⁻(aq) + Na⁺(aq)

The anion C₂H₃O₃⁻ originates from a weak acid, which thus goes through basic hydrolysis.

C₂H₃O₃⁻ + H₂O ⇄ C₂H₄O₃ + OH⁻

Given that the pKa for C₂H₄O₃ is 3.9, we can derive pKb for C₂H₃O₃⁻ using this relation:

pKa + pKb = 14

pKb = 14 - 3.9 = 10.1

10.1 = -log Kb

Kb = 7.9 × 10⁻¹¹

We can compute [OH⁻] through the equation:

[OH⁻] = √(Kb.Cb)               where Cb indicates the base's initial concentration

[OH⁻] = √(7.9 × 10⁻¹¹ × 0.012M) = 9.7 × 10⁻⁷ M

We can then find pOH and pH.

pOH = -log [OH⁻] = -log (9.7 × 10⁻⁷) = 6.0

pH + pOH = 14

pH = 14 - pOH = 14 - 6.0 = 8.0

According to the periodic table:
the molar mass of carbon is 12 g/mol
the molar mass of hydrogen stands at 1 g/mol
the molar mass of oxygen is 16 g/mol

the molar mass of <span>acetylsalicylic acid calculates to 9(12) + 8(1) + 4(16) = 180 g/mol

To find the number of moles, we apply the formula mass / molar mass = 0.5 / 180 = 2.778 x 10^-3 moles

To determine the number of molecules, we multiply the moles by Avogadro's number as shown:
number of molecules = </span>2.778x10^-3x6.02x10^23 =1.672 x 10^21 molecules