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irinina
1 day ago
15

what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current

in the bulb steady?
Physics
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An aluminum rod is 10.0 cm long and a steel rod is 80.0 cm long when both rods are at a temperature of 15°C. Both rods have the
serg [3582]

Response:

0.9 cm

Clarification:

The following illustrates the calculation of the combined rod's length increase:

As established

Length increase = expansion of aluminum rod + expansion of steel rod

= 10cm \times 2.4e - 5\times (90-15) + 80cm\times 1.2e - 5\times (90-15)

= 0.9 cm

We simply summed the expansions of both the aluminum and steel rods to determine the overall increase in the joined rod's length, which must be factored in

4 0
2 months ago
Ice fishermen sit on top of frozen lakes in the winter and catch fish in the liquid water below through holes cut in the ice she
Yuliya22 [3333]
This is due to the fact that below 4°c, water behaves differently than other substances and decreases in density as its temperature drops further.
8 0
1 month ago
Ben walks 500 meters from his house to the corner store. He then walks back toward his house, but continues 200 meters past his
Keith_Richards [3271]
Velocity = 71 meters per minute (MPM)
S stands for Speed
D means Distance
T represents Time
To calculate Speed, divide Distance by Time.
6 0
3 months ago
Read 2 more answers
A negatively charged object is located in a region of space where the electric field is uniform and points due north. the object
serg [3582]
- The greatest potential energy increase occurs when the charge travels north. This happens because the charge is negative, which means it gains potential energy when moving in the same direction as the field (in contrast, a positive charge moving along the field loses potential energy, converting it to kinetic energy). The potential energy gained is calculated as the charge multiplied by the distance moved:
\Delta U = e d

- The next largest increase occurs as the charge moves east. Here, the change in potential energy is actually zero since the charge moves perpendicular to the field, traversing points with constant potential. Therefore, there is no variation in potential energy in this case:
\Delta U = 0

- Finally, when the charge moves south, it experiences a reduction in potential energy. This is due to moving against the electric field, and since it is a negative charge, it loses potential energy in this direction, which transforms into kinetic energy. Thus, in this scenario:
\Delta U = - e d
5 0
2 months ago
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