Answer:
The amount of heat that enters the gas throughout this two-step process totals 120 cal.
Explanation:
Given that,
Moles present = 3
Heat capacity at volume held constant = 4.9 cal/mol.K
Heat capacity at pressure held constant = 6.9 cal/mol.K
Starting temperature = 300 K
Ending temperature = 320 K
We are tasked with determining the heat absorbed by the gas at constant pressure
Employing the heat formula

Substituting the values into the equation


Next, we calculate the heat absorbed by the gas at constant volume
Using the corresponding heat formula

Insert the values into the formula


Now, it's necessary to evaluate the total heat flow into the gas during both steps
Using the total heat formula



Thus, the heat that transfers into the gas throughout this two-step process amounts to 120 cal.