The formula for range is:
Given values are:
where θ equals 14.1 degrees
Using the equation above,
The calculated range is 66.7 meters.
Therefore, the range is approximately 66.1 meters.
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Answer:
A. Yes, the ball clears the crossbar by 2.83 meters
Explanation:
This situation pertains to projectile motion.
The horizontal velocity component of the ball is calculated as 26 cos 35 = 21.3 m/s
The vertical velocity component is 26 sin 35 = 14.9 m/s
The time taken to travel the horizontal distance to the goalpost, which is 54.9 m, is:
= distance / horizontal speed
= 54.9 / 21.3
= 2.577 seconds.
The vertical distance achieved during this time is:
h = ut - 1/2 gt², where u is the initial vertical velocity, and t = 2.577 seconds.
h = 14.9 x 2.577 - 0.5 x 9.8 x (2.577)²
= 38.39 - 32.54
= 5.85 m
Thus, the ball surpasses the crossbar by 5.85 - 3.05 = 2.8 m
