Answer:
Mass released = 8.6 g
Explanation:
Provided information:
Starting moles of nitrogen= 0.950 mol
Starting volume = 25.5 L
Final nitrogen mass released = ?
Final volume = 17.3 L
Calculation:
Equation:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Starting mass of nitrogen:
Mass = moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Ending mass of nitrogen:
Mass = moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - ending mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g