A flood that affects the environment where natural rubber is produced would severely hinder rubber production. In order to greatly limit production, a flood would need to destroy a significant portion of rubber trees. Natural rubber is crucial for manufacturing synthetic polymers. If the rubber supply is compromised (due to the disruption of its ecosystem caused by a flood), there would be a substantial decline in the availability of synthetic polymers.
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Answer:
The correct choice for your inquiry is option A, Argon.
Explanation:
Isotope Atomic mass Percent (%)
1 35.9675 0.337
2 37.9627 0.063
3 39.9624 99.6
To calculate the average atomic mass: (Mass of isotope 1)(percent of 1) + (Mass of isotope 2)(percent of 2) + (Mass of isotope 3)(percent of 3)
Average atomic mass = (35.9675)(0.00337) + (37.9627)(0.00063) + (39.9624)(0.996)
Average atomic mass = 0.1212 + 0.0239 + 39.8025
Average atomic mass = 39.9476
Theoretical Atomic mass
a) Ar 39.95
b) K 39.10
c) Cl 35.45
d) Ca 40.08
<span>Some solutions demonstrate colligative properties, which rely on the quantity of solute in a solvent. To find the elevation in boiling point, we use the formula:
</span><span>ΔT(boiling point) =
(Kb)mi
where Kb represents a constant, m is the solution's molality, and i is the van't Hoff factor.
From the provided information, we can easily determine i as follows:
</span>ΔT(boiling point) = (Kb)mi
103.45 - 100 = (0.512)3.90i
i = 1.73 <-------van't Hoff factor
Response:
H₂SO₄
Clarification:
Given a compound consisting of 0.475 g H, 7.557 g S, and 15.107 g O, we must compute the empirical formula by following specific steps.
Step 1: Compute the total mass of the compound
Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g
Total mass = 23.139 g
Step 2: Determine the percentage composition.
H: (0.475g/23.139g) × 100% = 2.05%
S: (7.557g/23.139g) × 100% = 32.66%
O: (15.107g/23.139g) × 100% = 65.29%
Step 3: Divide each percentage by the element's atomic mass
H: 2.05/1.01 = 2.03
S: 32.66/32.07 = 1.018
O: 65.29/16.00 = 4.081
Step 4: Normalize all values by the smallest one
H: 2.03/1.018 ≈ 2
S: 1.018/1.018 = 1
O: 4.081/1.018 ≈ 4
Thus, the empirical formula for the compound is H₂SO₄.
Explanation:
Filtration serves as a method of separation where solid particles that are suspended in a liquid are isolated by passing the mixture through filter paper's pores. This process ensures that the solid particles accumulate on the filter paper and the liquid flows out through the filter paper's pores.
The ordered sequence of the steps provided is:
- Measure and fold the filter paper.
- Insert the filter paper into the funnel, then position the funnel above the Erlenmeyer flask.
- Let the solid/liquid mixture pass through the filter.
- Rinse the filter paper that holds the mixture with water.
- Measure the weight of the dry filter paper along with the copper.
