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Nataliya
18 days ago
12

What is the displacement of a runner who is running at 0.5km/h for 3 hours due north

Physics
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In a movie, Tarzan evades his captors by hiding under water for many minutes while breathing through a long, thin reed. Assume t
inna [3103]
The maximum depth at which he could still breathe, given the pressure of -74 mm Hg, equates to 0.98 m. Pressure of -74 mm Hg translates to 9605 Pa or 9709 N/m². With the density of water set at 1000 kg/m³, we can utilize the pressure equation P = rho g h to determine h, deriving that h = 0.98 m.
8 0
2 months ago
Assume you are driving 20 mph on a straight road. Also, assume that at a speed of 20 miles per hour, it takes 100 feet to stop.
Maru [3345]

Answer:900 feet

Explanation:

Given

Velocity \left ( V_1\right )=20 mph\approx 29.334 ft/s

It takes 100 feet to come to a stop.

Utilizing the equation of motion

v^2-u^2=2as

Where

v,u=Final and initial velocities

a=acceleration

s=distance traveled

0-\left ( 29.334\right )^2=2\left (-a\right )\left ( 100\right )

a=\frac{29.334^2}{2\times 100}=4.302 ft/s^2

When the speed is 60 mph \approx 88.002 ft/s

v^2-u^2=2as

0-\left ( 88.002\right )^2=2\left ( -4.302\right )\left ( s\right )

s=900.08 feet

8 0
4 months ago
Read 2 more answers
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Keith_Richards [3271]
The rise in fluid level is 0.11 m, and for mercury, it is 0.728 cm or 7.28 mm. \nTo solve this, here’s the information we have: \n- Density of oil: [density value] \n- Change in pressure in the tank: [pressure change] \n- Density of mercury: [density value] \nTo find the fluid level rise in the manometer: \n1 mmHg equals 133.332 Pa. \nBased on the variables: g is the acceleration due to gravity and h represents the height of the fluid level. \nh = 0.11 m. \nUsing mercury, we find: \nh = 0.00728 m, which is 7.28 mm.
5 0
2 months ago
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