Answer:
Explanation:
For a 60W light bulb used for 1 minute:
P = 60 W
t = 1 minute = 60 seconds
This energy is capable of lifting an object weighing 10N.
W = 10N
This indicates conversion of electrical energy into potential energy.
Let's calculate the electrical energy:
Power describes the rate of work done.
Power = Work / time
Thus, work = power × time
Work = 60 × 60
Work = 3600 J
Potential energy calculation:
P.E = mgh
Where the weight is given by:
W = mg
Therefore, P.E = W·h
P.E = 10·h
Thus, we equate:
Potential energy = Electrical energy
P.E = Work
10·h = 3600
Dividing both sides by 10 gives:
h = 3600 / 10
h = 360m
The object can be lifted to a height of 360m.
Response:
Clarification:
We need an expression that shows how much water has been drained from the tub. This is represented by v, which indicates how many gallons have flowed out since the plug was taken out. Each gallon removed equates to 8.345 pounds of water, so the weight of the drained water Q in pounds as a function of v can be expressed as:
Where v signifies the number of gallons emptied from the tub.
Have a great day! Let me know if there's anything else I can assist with.
To tackle this question, we know the following:
1 Albert equals 88 meters.
1 A = 88 m.
Initially, we square both sides of the equation:
(1 A)^2 = (88 m)^2
1 A^2 = 7,744 m^2
<span>Since 1 acre equals 4,050 m^2, let’s divide both sides by 7,744 to find out how many acres match this value:</span>
1 A^2 / 7,744 = 7,744 m^2 / 7,744
(1 / 7,744) A^2 = 1 m^2
Then multiply both sides by 4,050.
(4050 / 7744) A^2 = 4050 m^2
0.523 A^2 = 4050 m^2
<span>Thus, one acre is approximately 0.52 square alberts.</span>
Answer:
A) and B) are valid.
Explanation:
When an object remains at rest, it is indicative that no net force acts upon it.
The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.
This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).
At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.
Thus, statements A) and B) are true.
