Let's denote the orbital period of planet X as T and its average distance from the sun as A. For planet Y, let its orbital period be T_1, implying that if planet Y's mean distance from the sun is twice that of planet X:

This indicates that the orbital period for planet Y increases by a factor of 
Response:
15:6 = 5:2=28:x
x=11.2, approximately 12 hours.
Step-by-step explanation:
Response:
The measure of mHLK is "(204)°".
Step-by-step breakdown:
Given values include:
mJI = (3x+2)°
mHLK = (15x-36)°
and,
m∠HML = (8x-1)°
then,
What is mHLK?
Now,
Utilizing the chord-chord angle formula, we find

Inserting the known values into the equation gives us
⇒ 
By carrying out cross-multiplication, we arrive at
⇒ 
⇒ 
By subtracting "18x" from both sides, we obtain
⇒ 
⇒ 
Upon adding "2" to both sides, we end up with
⇒ 
⇒ 
⇒ 
⇒ 
By substituting the value of "x" into mHLK = (15x-36)°, we calculate
⇒ (15x-36)° = (15×16-36)°
⇒ = (240-36)°
⇒ = (204)°
Thus, mHLK = (204)°