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Mashcka
16 days ago
10

A spaceship is headed toward Alpha Centauri at 0.999c. According to us, the distance to Alpha Centauri is about 4 light-years. H

ow far away is Alpha Centauri according to the travelers in the ship?
a) also about 4 light-years
b) very slightly more than 4 light-years
c) very slightly less than 4 light-years
d) quite a bit less than 4 light-years
e) quite a bit more than 4 light-years
Physics
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For lunch you and your friends decide to stop at the nearest deli and have a sandwich made fresh for you with 0.300 kg of Italia
serg [3582]

Answer:

Part a)

A = 0.0581 m

Part b)

T = 0.37 s

Explanation:

A slice is dropped onto the plate from a height of 0.250 m,

therefore the speed of the slice upon impact is calculated as

v = \sqrt{2gh}

We know that

v = \sqrt{2(9.81)(0.250)}

v = 2.21 m/s

Now applying the conservation of momentum:

mv = (m + M)v_f

m = 0.300 kg

M = 0.400 kg

From this equation, we find:

0.300 (2.21) = (0.300 + 0.400) v_f

v_f = 0.95 m/s

0.400 (9.81) = 200 x_1

When the slice rests on the plate, the new mean position can be expressed as

x_1 = 0.01962 m

(0.300 + 0.400)9.81 = 200 x_2

We also determine that the speed of SHM is represented as

x_2 = 0.0343 m

Here, we derive values from

v = \omega\sqrt{A^2 - x^2}

\omega = \sqrt{\frac{k}{m + M}}

\omega = \sqrt{\frac{200}{0.300 + 0.400}}

\omega = 16.9 rad/s

a = x_2 - x_1 = 0.0343 - 0.01962 = 0.0147 m

Using the previous formula gives:

0.95 = 16.9\sqrt{A^2 - 0.0147^2}

A = 0.0581 m

Part b)

The time period for the scale is computed as

T = \frac{2\pi}{\omega}

T = \frac{2\pi}{16.9}

T = 0.37 s

8 0
3 months ago
Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal,
Maru [3345]

Answer: yes.

Explanation: The type of light striking the metal is visible light.

There are three factors involved:

1. The temperature

2. The specific heat of the metal

3. The thermal conductivity of the metal.

The increase in temperature of the metal is influenced by how light energy is absorbed and reflected; it will absorb some of the energy and won't reflect all of it.

When an object absorbs visible light, it transforms the short wavelength light into longer wavelength heat, leading to a temperature rise.

6 0
3 months ago
A long plastic rod of 20-mm diameter (k = 0.3 W/m · K and rhocp = 1040 kJ/m3 · K) is uniformly heated in an oven as preparation
inna [3103]

Response:

The temperature required to achieve this is 286.7°C.

Justification:

Provided information:

Diameter = 20 mm = 0.02 m

Le = characteristic length = 0.02/4 = 5x10⁻³m

Thermal conductivity (K) = 0.3 W/m K

Density times specific heat (ρCp) = 1040 kJ/m³ K = 1.04x10⁶

Time (t) = 3 minutes = 180 seconds

Convection heat transfer coefficient (h) = 10 W/m² K

According to transient heat analysis:

\frac{T-25}{T_{o}-25 } =e^{-(\frac{h}{L_{e}\rho Cp } )t}

\frac{200-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6} })*180 } \\T_{o} =272.38C

200°C is the minimum temperature requirement; thus, we assume a value of 210°C (10°C higher) to calculate the necessary temperature:

\frac{210-25}{T_{o} -25} =e^{-(\frac{10}{5x10^{-3}*1.04x10^{6} })*180 } \\T_{o} =286.7C

6 0
3 months ago
Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish
Sav [3153]

Response:

In this scenario, the refractive index of seawater is 1.33, while the index for air is 1. Because of this, the refraction angle is smaller than the angle of incidence, making the fish appear closer

Conversely, when viewed from the fish's perspective looking at a person's face, the angle has increased, making the person appear further away

Clarification:

This discussion is analyzed by applying the refraction law, which states that when a light ray crosses from one medium to another, its path bends due to differing indices of refraction,[ [TAG_20]]

n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices and θ represents the angles for each medium.

Here, with seawater being 1.33 and air at 1, the refraction angle remains lesser than the angle of incidence, leading to the fish appearing nearer

1 sin θ₁ = 1.33 sin θ₂

θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)

When the fish gazes at the human face, the angle's reason increases, hence making the face seem more distant

4 0
2 months ago
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