First, we must transform the pressure into SI units, considering that
:
The starting and ending volumes of the gas will be as follows (keeping in mind that
):
Thus, the work performed on the gas by its surroundings is
The positive outcome indicates that this work leads to a rise in the gas's internal energy.
It may lead to higher levels of homocysteine, which can harm the inner linings of arteries. Such damage often results from unwanted clotting that can occur due to factors like smoking, which tends to raise unwanted blood clots in the body, ultimately causing these levels to rise and resulting in undesired consequences.
Response:
Magnitude of the electrostatic force acting on the +32 µC charge, 
Clarification:
Let q₁ = +32 µC, located at x₁ = 0
q₂ = +20 µC, positioned at x₂ = 40 cm = 0.4 m
q₃ = -60 µC, placed at x₃ = 60 cm = 0.6 m
Define the force magnitude on the +32 µC charge from the +20 µC charge as F₁ (the force on q₁ due to q₂).
Define the force magnitude on the +32 µC charge from the -60 µC charge as F₂ (the force on q₁ due to q₃).
The resultant electrostatic force on the 32 µC charge is 
H = 40 m is the height from which the ball is released.
m = 1 kg is the ball's mass
Assuming g = 9.8 m/s² and disregarding air resistance.
The vertical velocity at the start is zero.
Let t be the flight duration, then
40 m = (1/2)*g*(t s)² = 0.5*9.8*t²
t² = 40/4.9 = 8.1633
t = 2.857 s
Result: 2.9 s (rounded to the nearest tenth)
Answer:
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Explanation:
