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Eduardwww
3 months ago
5

Tyrel is learning about a certain kind of metal used to make satellites. He learns that infrared light is absorbed by the metal,

X-ray light is transmitted through the metal, and visible light is reflected off the metal. Tyrel wonders of the metal will get warm if he shines the lights on it. Can light cause the metal to get warm?
Physics
1 answer:
Maru [3.3K]3 months ago
6 0

Answer: yes.

Explanation: The type of light striking the metal is visible light.

There are three factors involved:

1. The temperature

2. The specific heat of the metal

3. The thermal conductivity of the metal.

The increase in temperature of the metal is influenced by how light energy is absorbed and reflected; it will absorb some of the energy and won't reflect all of it.

When an object absorbs visible light, it transforms the short wavelength light into longer wavelength heat, leading to a temperature rise.

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A person is rowing across the river with a velocity of 4.5 km/hr northward. The river is flowing eastward at 3.5 km/hr (Figure 4
Yuliya22 [3333]

Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.

Explanation:

Let Q be the speed of the boat, and P be the speed of the river flow.

R represents the resultant velocity combining boat velocity and river current.

According to vector addition using the law of triangles:

R=\sqrt{P^2+Q^2+2PQCos\theta}

From the diagram:

P = 3.5 km/h, Q = 4.5 km/h

\theta= 90^o

R=\sqrt{P^2+Q^2+2PQCos\theta}=\sqrt{(3.5)^2+(4.5)^2+3.5\times 4.5\times cos90^o}=5.70

(Cos90^o=0),(sin 90^o=1)

\alpha =tan^{-1}\frac{Qsin\theta}{P+Qcos\theta}=tan^{-1}\frac{4.5 sin 90^o}{3.5+4.5 cos90^o}=tan^{-1}\frac{4.5}{3.5}=52.12^o

Therefore, her velocity magnitude relative to the shore is 5.70 km/h.

8 0
3 months ago
Digital bits on a 12.0-cm diameter audio CD are encoded along an outward spiraling path that starts at radius R1=2.5cm and finis
Sav [3153]

Answer:

The overall length of the spiral, designated as L, is calculated to be 5378.01 m

Explanation:

Provided information:

Inner radius R1=2.5 cm

and outer radius R2= 5.8 cm.

The thickness of the spiral winding is (d) =1.6 \mu m = 1.6x 10^{-6} m

The total length of the spiral can be computed as

= \frac{(Area\ of\ the\ spiraing\ portion\ on\ the\ disk)}{d}

=\frac{\pi *(R_2)^2 - \pi*(R_1)^2}{d}

=\frac{\pi *(0.058)^2 - \pi*(0.025)^2}{1.6*10^{-6}}

= 5378.01 m

5 0
3 months ago
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